Info

La pregunta está cerrada. Vuélvala a abrir para editarla o responderla.

Can this dsolve code find solution recursively

1 visualización (últimos 30 días)
MINATI PATRA
MINATI PATRA el 20 de Oct. de 2020
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
syms x f f0(x) f1(x) f2(x) f3(x) f4(x) f5(x) f6(x)
eqn0 = diff(f1,3) == 0; cond0 = [f1(0) == 0, subs(diff(f1),0) == 0, subs(diff(f1),5) == 1 ];
f1 = dsolve(eqn0,cond0);
for m = 2:6
syms f_m
for k = 1:(m-1)
Df = diff(f); D2f = diff(Df); D3f = diff(D2f);
eqn(k) = D3f + (1/2)* f * D2f == 0;
cond(k) = [subs(f,0) == 0, subs(Df,0) == 0, subs(Df,5) == 0];
F = dsolve(eqn(k),cond(k)); f(k) = F.f(k)
end
end
disp([f2 f5 f])
%% I need (f1) to include in the loop to carry the solution and Please help me to run the code.
N.B: Two boundary conditions are different
PLEASE FOLLOW the attached pdf

Respuestas (0)

La pregunta está cerrada.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by