Index in position 2 exceeds array bounds (must not exceed 8)

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I keep getting the error "Index in position 2 exceeds array bounds (must not exceed 8) with the following code. I am trying to determine whether a matrix is strictly diagonally dominant or not. The error appears on the line with sumrow=sumrow+abs(A(i,j));
This is the code.
A = [28 -6 4 1 -2 -5 8 0;
-4 28 -1 4 0 4 4 6;
1 -6 26 -5 1 -1 -6 0;
1 -6 26 -5 1 -1 -6 0;
-5 -6 1 21 0 -3 2 2;
4 1 3 -3 17 0 -3 3;
4 -2 3 0 2 14 0 1;
1 2 4 3 -2 1 17 4;
1 3 1 3 0 -1 3 15];
rowcol=size(A);
n=rowcol(1);
count=0;
for i=1:1:n
sumrow=0;
for j=1:1:n
if i~=j
sumrow=sumrow+abs(A(i,j));
end
end
if abs(A(i,i))>sumrow
count=count+1;
end
end
if count==n
disp('Matrix is strictly diagonal dominant')
else
disp('Matrix is NOT strictly diagonal dominant')
end
Any help with corrections will be greatly appreciated.
  1 comentario
Rik
Rik el 21 de Oct. de 2020
Regarding your flag: what would make this question a duplicate?
Just in case you will try to edit away your question: I made a capture to the Wayback Machine, so everyone with editing priviliges can put your question back the way it is now.

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Respuesta aceptada

Asad (Mehrzad) Khoddam
Asad (Mehrzad) Khoddam el 20 de Oct. de 2020
The matrix is not square, so you need to find the minimum of row and column numbers.
A = [28 -6 4 1 -2 -5 8 0; -4 28 -1 4 0 4 4 6; 1 -6 26 -5 1 -1 -6 0; 1 -6 26 -5 1 -1 -6 0; -5 -6 1 21 0 -3 2 2; 4 1 3 -3 17 0 -3 3; 4 -2 3 0 2 14 0 1; 1 2 4 3 -2 1 17 4; 1 3 1 3 0 -1 3 15];
rowcol=size(A);
n=min(size(A));
count=0;
for i=1:1:n
sumrow=0;
for j=1:1:n
if i~=j
sumrow=sumrow+abs(A(i,j));
end
end
if abs(A(i,i))>sumrow
count=count+1;
end
end
if count==n
disp('Matrix is strictly diagonal dominant')
else
disp('Matrix is NOT strictly diagonal dominant')
end

Más respuestas (1)

Cris LaPierre
Cris LaPierre el 20 de Oct. de 2020
Editada: Cris LaPierre el 20 de Oct. de 2020
The issue I see is that you are assuming A is square (8x8), but it is not. It has dimensions 9x8. However, you are only using the first number, 9, to loop through the rows and columns of A. This is causing an error in your second for loop (j=9).
Try
...
for i=1:size(A,1)
...
for j=1:size(A,2)
...
end
...
end
...
  1 comentario
Image Analyst
Image Analyst el 20 de Oct. de 2020
Plus you should really be more general like this:
[rows, columns] = size(A);
count=0;
for row = 1 : rows
sumrow = 0;
for col = 1 columns
etc. The above code does not depend on the number of rows matching the number of columns. If you need them to match, you should check for that in advance of the for loop:
[rows, columns] = size(A);
if rows ~= columns
errorMessage = sprintf('Error : rows and columns do not match. Rows = %d while columns = %d', rows, columns);
uiwait(errordlg(errorMessage));
return; % Quit this function/module.
end
for row = 1 : rows
sumrow = 0;
for col = 1 columns

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