find text in text file

I want to find a specific text line in my text file, how do i code this? In this code I want to fill in time and then get the number of colum two, is there anybody who can help?
09:48:40 0 1
09:48:42 0 1
09:48:44 0 1
09:48:46 0 1
09:48:48 0 1
09:48:50 0 1
09:48:52 0 1
09:48:54 0 1
09:48:56 1788 1
09:48:58 0 1
09:49:00 0 1
09:49:02 0 1

4 comentarios

Mario Malic
Mario Malic el 25 de Oct. de 2020
Walter Roberson
Walter Roberson el 25 de Oct. de 2020
If you use a timetable object then you can index directly by the time.
sander de lange
sander de lange el 25 de Oct. de 2020
Hi guys Thanks for the quick reaction. However I think wasn't that clear. But what I want is a code/function that gives me the linenumber of for example 9:48:56. Can you guys help me with that?
Peter Perkins
Peter Perkins el 19 de Nov. de 2020
+1 to Walter's suggestion. Make a timetable with duration row times, then just use 9:48:56 as a row subscript, perhaps as tt('9:48:56',:) or perhaps as tt.Var1('9:48:56').

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Respuestas (2)

Stephen23
Stephen23 el 25 de Oct. de 2020

0 votos

>> T = readtable('temp0.txt','Delimiter','\t','ReadVariableNames',false)
T =
Var1 Var2 Var3
__________ ____ ____
'09:48:40' 0 1
'09:48:42' 0 1
'09:48:44' 0 1
'09:48:46' 0 1
'09:48:48' 0 1
'09:48:50' 0 1
'09:48:52' 0 1
'09:48:54' 0 1
'09:48:56' 1788 1
'09:48:58' 0 1
'09:49:00' 0 1
'09:49:02' 0 1
>> X = strcmp(T.Var1,'09:48:56');
>> Y = T.Var2(X)
Y =
1788
Walter Roberson
Walter Roberson el 25 de Oct. de 2020

0 votos

fileread and regexp() 'split' using pattern '\r?\n' on that to get lines. Now regexp() that cell array of character vectors giving the target time as the pattern and 'once' option. cellfun @isempty and ~ the resulting vector and find() to get the line number.
This for the new requirement that the desired output is the line number. The code for the original task of extracting the second column would have been notably simpler.

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el 25 de Oct. de 2020

Comentada:

el 19 de Nov. de 2020

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