Create an array of file names produced by system('dir /S *.ext')
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bugguts99
el 27 de Abr. de 2011
Comentada: Seung-Goo Kim
el 14 de Oct. de 2022
Hi there,
I know that you can search directories and sub-directories to provide a list of file names that meet a particular criteria using the code below:
[status,list]=system('dir /S *.mp3');
My question is: is it possible to create an array from the file names generated this way in order to create a loop for further processing??
Thanks in advance...
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Richard Alcock
el 27 de Abr. de 2011
You can use textscan to split the multiple lines of output from the system command into a cell array.
[status, list] = system( 'dir /B /S *.mp3' );
result = textscan( list, '%s', 'delimiter', '\n' );
fileList = result{1}
Note that I've added /B to the dir command to make the output easier to parse.
2 comentarios
franco otaola
el 7 de Oct. de 2016
is there any possibility of extract the name without the extension? thanks
Más respuestas (1)
Sven Mesecke
el 27 de Abr. de 2011
What's wrong with the MATLAB function 'dir'? You can add wildcards like .mp3 and get a struct array in return, whose name field can easily be converted into a cell array of filenames:
a=dir('S/*.ext');
b={a.name}
Otherwise there's a nice tool on MATLAB Central that uses regular expressions for dir: http://www.mathworks.com/matlabcentral/fileexchange/16216-regexpdir
5 comentarios
Seung-Goo Kim
el 14 de Oct. de 2022
@nvmnghia you can try it yourself on your computer. But now MATLAB supports something like Jupyter notebook on a virtual environment:
pwd
unix('echo"" > thisfile1.txt'); unix('echo"" > ThatFile-1234.txt');
a = dir('*.txt')
b = [a.name]
This will create a very wide character array by horizontally concatenating cated character arrays (i.e., file names). Then it becomes another problem to access each file. You usually can't do vertical concatenation because often the file names have different number of characters.
b = cat(1,a.name)
So, this is why you want to cast them into a cell array, instead of a character array, as @Sven Mesecke wrote above.
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