How to fix it.
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Nisar Ahmed
el 28 de Oct. de 2020
Comentada: Nisar Ahmed
el 28 de Oct. de 2020
wav dimentions are
wav = 5001*1
and I want to change it as wav = 5001*5
How I can reshape it?
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Steven Lord
el 28 de Oct. de 2020
So you want to take 5001 values and generate 25005 (5001 times 5) values using those values. How do you want to generate the additional 20004 values?
Make duplicate copies?
x = (1:6).'
y = repmat(x, 1, 5)
Offset the copies by a certain amount? This approach uses implicit expansion; if you're using an older release you could use bsxfun.
x = (1:6).'
y = x + (0:10:40)
Pad with 0 values or with random data?
x = (1:6).'
y = [x, zeros(size(x, 1), 5)]
z = [x, rand(size(x, 1), 5)]
w = [x, randi([7 11], size(x, 1), 5)]
Something else? If so, please explain in detail how you want to generate the additional values.
3 comentarios
Elijah McNeil
el 28 de Oct. de 2020
His code does that, Just write this.
x = (1:5000).';
wav = repmat(x, 1, 5).
Más respuestas (1)
Elijah McNeil
el 28 de Oct. de 2020
Editada: Elijah McNeil
el 28 de Oct. de 2020
This should work
wav = 5001*1
wav = wav*5
5 comentarios
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