How to calculate sum of power series

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DARREN O BRIEN
DARREN O BRIEN el 30 de Oct. de 2020
Comentada: Ameer Hamza el 30 de Oct. de 2020
i cant get the code the work
im trying to write a(n+2)=(a(n+1)a(n+1)-b*a*n-2)/(n+2)(n+1)
but the variable a and b are tripping me up
and this error keep coming up
Error: Invalid expression. When calling a function or
indexing a variable, use parentheses. Otherwise, check
for mismatched delimiters.
n=5;
for i=1:n
p=(((a*n+1*a*n+1-b*a*n-2)/(n+2*n+1);
end
  1 comentario
Ameer Hamza
Ameer Hamza el 30 de Oct. de 2020
It seems that the there are mistakes in expression
a(n+2)=(a(n+1)a(n+1)-b*a*n-2)/(n+2)(n+1)
can you show from where did you get this series? Is there a known name for this? Can you attach the original source for this series.

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KSSV
KSSV el 30 de Oct. de 2020
Editada: KSSV el 30 de Oct. de 2020
n=5;
a = rand ;
b = rand ;
p = 0 ;
for i=1:n
p=p+ (a*n+1*a*n+1-b*a*n-2)/(n+2*n+1); % check the expression though
end

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