Subtracting two matrices of different size element by element
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Algorithms Analyst
el 21 de Feb. de 2013
Comentada: Image Analyst
el 13 de Sept. de 2014
Hi every one
is there any way how to subtradt two matrices of different dimension let say A=ones(40) and B=ones(12)
How can we perform subtraction like S=A-B.
Thanks
0 comentarios
Respuesta aceptada
Azzi Abdelmalek
el 21 de Feb. de 2013
% ----------your data-------
x=magic(4);
y=magic(2);
%-----------The code-----------
[n,m]=size(x);
[n1,m1]=size(y);
z=zeros(n,m);
z(1:n1,1:m1)=y
out=x-z
2 comentarios
rana Banik
el 13 de Sept. de 2014
Editada: Image Analyst
el 13 de Sept. de 2014
doesn't work! I have this function to perform.
distance=IMM-c;
>>whos
IMM= 132x116x2 double
c= 132x348x2 double
I have also performed bsxfun command but each time command window says error in array mismatch!!! have any other way ??
Image Analyst
el 13 de Sept. de 2014
Azzi's method does not subtract the entire arrays - that is impossible. You either have to resize one of them like I suggested in my answer, or just subtract some overlapping part, like Azzi's answer which the original poster accepted. rana, for your situation you need to subtract only the first 116 columns
distance = IMM - c(:,1:size(IMM, 2), :);
It would be more robust to actually take the minimum of each dimension of the two arrays to determine the ending row, column, and third dimension.
Más respuestas (1)
Image Analyst
el 21 de Feb. de 2013
Not unless you resize one of them. But actually we'd need an actual example with actual arrays so we can understand your thought process. Please give us an example where it does exactly what you want and we can maybe tell you how to achieve that.
3 comentarios
Thorsten
el 21 de Feb. de 2013
It would be helpful if you give an example, e.g., what should be the result of
[1 2 3] - [4 5]
Ver también
Categorías
Más información sobre Resizing and Reshaping Matrices en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!