Making a Riemann Sums function with multiple n values

1 visualización (últimos 30 días)
Gurinder Punni
Gurinder Punni el 12 de Nov. de 2020
clc;clear;
fun = input('what is the function: ');
a = input('what is a: ');
b = input('what is b: ');
n = input('what is n: ');
N=length(n);
h = (b-a)/N;
sum = 0;
for j=1:N
h(j) = (b-a)/n(j);
sum(j) =fun(a+h(j)*(j-1));
end
sum(n) = sum(n).*h(n);
disp(sum)
So, I am trying to create a Riemann sums function and want the final value to be an array of the chosen n values, e.g. n = 1:10. So, the values as you increase should become more accurate to the actual integral. But, When I look at the results, they just get smaller over time not even close to the actual value. When I was trying to find the integral with just 1 n, I got a pretty close value to the actual integral. I am not sure what I did wrong in converting it to an array format.

Respuestas (0)

Categorías

Más información sobre Mathematics en Help Center y File Exchange.

Etiquetas

Productos


Versión

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by