why doesnt it works

for i = 1 :1: N
for j = 1 :1: N
if u(i,j) < 1-a(i,j) && N<1- (u(i,j)/(1-a(i,j)))
z= (1-a(i,j))*N
end
end
end

4 comentarios

Rik
Rik el 17 de Nov. de 2020
This time I edited your question for you. Next time, please use the tools explained on this page to make your question more readable.
What do you mean by 'it doesn't work'?
Peter Perkins
Peter Perkins el 19 de Nov. de 2020
Also, you don't need loops at all.
z = zeros(size(a));
i = (u < 1-a) && (N < 1 - u./(1-a))
z(i) = (1-a(i)) .* N;
Nirajan Khatri
Nirajan Khatri el 20 de Nov. de 2020
@ Rik thank you, i have u matrix and a matrix so i was trying to use conditional loop, next time i will surely do it
Nirajan Khatri
Nirajan Khatri el 20 de Nov. de 2020
@ Peter Perkins Sir thank you

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el 17 de Nov. de 2020

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