Diode i-v Curve Graph

Hello,

I need help to graph that diode i-v curve. my code is here;

clc
clear all
n = 1.65;    %Ideality factor
Is = 220*10^-12;  % diode reverse saturated current
q = 1.602*10^-19;    % electron charge
K = 1.38*10^-23; %Boltzmann constant
T = 300;    % Absolute temperature
Vd = ((n.*K.*T)./q).*log((Is./Id)+1);
Id = Is*(exp((q*Vd)./(1.65*K*T))-1);

plot(Vd,Id)
hold on
ylabel('Id')
xlabel('Vd')

Id and Vd values are depending each other so how can graph that depending values?

Answer 1

[Mohamad]

Try this , change voltage vaues as you need .

clc
clear all
n = 1.65;    %Ideality factor
Is = 220*10^-12;  % diode reverse saturated current
q = 1.602*10^-19;    % electron charge
K = 1.38*10^-23; %Boltzmann constant
T = 300;    % Absolute temperature
fs=1000;
dv=1/fs;
v0=-0.3 ; % change as you want
vend=1.1 ; % change as you want
Vd=v0:dv:vend;
Id = Is*(exp((q*Vd)./(1.65*K*T))-1);
plot(1000*Vd,Id) ; grid ; xlabel(' Diode Voltage in mV ' ) ; ylabel(' Diode Current in Amp. ')

[Fulden Ece Ugur]

Thank you so much for your help :)

[Mohamad]

Ok , thanks , please accept the answer for the question

[Ashish Kulkarni]

How will you plot the reverse breakdown voltage here? For which diode are these paramaters specified.

I tried upto 100 V, but it is giving only a straight line.

Answer 2

[Sumit Debnath]

n = 1.65; %Ideality factor

Is = 220*10^-12; % diode reverse saturated current

q = 1.602*10^-19; % electron charge

K = 1.38*10^-23; %Boltzmann constant

T = 300; % Absolute temperature

Vd = ((n.*K.*T)./q).*log((Is./Id)+1);

Id = Is*(exp((q*Vd)./(1.65*K*T))-1);

plot(Vd,Id)

hold on

ylabel('Id')

xlabel('Vd')

Answer 3

[Khuzaim]

Use “exponential model with graphical analysis” to

determine VD1, VD2, VD3, ID1, ID2, ID3. Assume that the diode has a current of 0.5 mA at a

voltage of 0.7 V.

Answer 4

[Md. Zamil Hasan Shovon]

I = Iph - Io [exp(V/n*Vt) – 1]