What does this mean? (Attempted to access Q(0); index must be a positive integer or logical.)

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I am trying to use the formula Q(t ) = CV(1 − e−t/RC ) to monitor the charge on the capacitor every .2 seconds given V = 9,R = 4, C = 1, and Q at t(0) = 0. We are supposed to display the time and charge every .1 seconds until Q exceeds 8.
This is my code so far:
Q(0)=0;
V = 9; %Voltage
R = 4; %Resistor Value
C = 1; %Capacitor Value
p = 0;
t = .1; %Time
for Q = 0:8
Q(t) = C * V * (1-exp(-(p+t)/(R * C))); %Charge Function
plot (Q(t),'c+')
end
When I attempt to evaluate the code i keep getting this:
Attempted to access Q(0); index must be a positive integer or logical.
Thank you

Respuestas (2)

Azzi Abdelmalek
Azzi Abdelmalek el 10 de Mzo. de 2013
Editada: Azzi Abdelmalek el 10 de Mzo. de 2013
In Matlab you can not use
A(0) or A(-1) or A(1.5)
index must be a positive integer or logical:
Positive integer are: 1,2,3,...
Logical are: logical(0) and logical(1)
  2 comentarios
Turk
Turk el 10 de Mzo. de 2013
now when I change the Q(0) to Q(1) I get:
>> Q(1)=0;
V = 9; %Voltage
R = 4; %Resistor Value
C = 1; %Capacitor Value
p = 0;
t = .1; %Time
for Q = 0:8
Q(t) = C * V * (1-exp(-(p+t)/(R * C))); %Charge Function
plot (Q(t),'c+')
end
Attempted to access Q(0.1); index must be a positive integer or logical.
How would you correct this? I am not that good at Matlab yet sadly..
Azzi Abdelmalek
Azzi Abdelmalek el 10 de Mzo. de 2013
Yes, you can not use Q(0.1) because 0.1 is not positive integer

Iniciar sesión para comentar.


Daniel Shub
Daniel Shub el 10 de Mzo. de 2013
Your for loop doesn't make any sense. It is a bad idea to iterate on a variable that you then change within a for loop (in this case Q). Further, t is a non-integer value so cannot be used to index Q. Finally plot (Q(t),'c+') is probably not doing what you expect.
MATLAB comes with some really great documentation. I suggest reading it.

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