How to solve this matrix using inverse function?
4 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
I want to use the inverse function (inv) on this 10 x 10 matrix but I keep getting all this Inf in place of the numbers.
The matrix goes as follows,
clc,clear all
a = [1 2 3 4 5 6 7 8 9 10];
b = [21 22 23 24 25 26 27 28 29 30];
c = [11 12 13 14 15 16 17 18 19 20];
d = [31 32 33 34 35 36 37 38 39 40];
f = [41 42 43 44 45 46 47 48 49 50];
g = [61 62 63 64 65 66 67 68 69 70];
h = [51 52 53 54 55 56 57 58 59 60];
i = [81 82 83 84 85 86 87 88 89 90];
j = [91 92 93 94 95 96 97 98 99 100];
e = [1 2 3 4 5 6 7 8 9 10];
aa = sum(a);
bb = sum(b);
cc = sum(c);
dd = sum(d);
ff = sum(f);
gg = sum(g);
hh = sum(h);
ii = sum(i);
jj = sum(j);
ee = sum(e);
AA = [a ;b ;c ;d ;e ;f ;g ;h ;i ;j];
b = [aa ;bb ;cc ;dd ;ff ;gg ;hh ;ii ;jj ;ee];
Res = inv(A)
The result I am getting is this one,
Warning: Matrix is singular to working precision.
> In borrame at 39
Res =
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Why if the command (inv) not working? Please help.
0 comentarios
Respuesta aceptada
James Tursa
el 15 de Mzo. de 2013
Assuming inv(A) is a typo and you really meant inv(AA):
"a" and "e" are the same, so you have two rows in AA that are the same. This linear dependency creates a singular matrix AA.
0 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Linear Algebra en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!