Info

La pregunta está cerrada. Vuélvala a abrir para editarla o responderla.

Increasing value of filter till required number of solutions each reached

1 visualización (últimos 30 días)
Afzal
Afzal el 21 de Mzo. de 2013
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
I need a while loop to increase the length, n, of a filter until I have 8 values that satisfy a result. The code that I have does not seem to work.
index = [];
while length(index)>8
n = 1;
filtered_ipam_relative_hand_position = moving_average_filter(ipam_relative_hand_position, n);
velocity=zeros(size(filtered_ipam_relative_hand_position));
for i=1:length(data)
for j= 1:3
x = i-1;
y = i+1;
if x == 0
x = 1;
else
if i == length(data)
y = length(data);
end
end
velocity(i,j) = (filtered_ipam_relative_hand_position(y,j)- filtered_ipam_relative_hand_position(x,j))/0.08;
end
end
magnitude_velocity = zeros(length(velocity),1);
for i=1:length(data)
magnitude_velocity(i)=((velocity(i,1))^2 + (velocity(i,2))^2 + (velocity(i,3))^2)^0.5;
end
for i=1:length(data)-1
if (magnitude_velocity(i+1,1)<0.01) && (magnitude_velocity(i,1)>0.01)
index = [index i];
end
end
n=n+1;
end

Respuestas (1)

Walter Roberson
Walter Roberson el 22 de Mzo. de 2013
length([]) is 0, which is <= 8, so your "while" loop never executes.
  2 comentarios
Afzal
Afzal el 23 de Mzo. de 2013
How should I define 'index' then?
Walter Roberson
Walter Roberson el 26 de Mzo. de 2013
The problem is not your definition of "index", the problem is your "while" condition.

La pregunta está cerrada.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by