how to index a matrix by using a index matrix that has same size?
2 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
I have a m by n data matrix and a m by n index matrix which rearranges the order of the n elements in each row of the data matrix. How can I get an indexed data matrix without using loop? Thanks.
1 comentario
Respuesta aceptada
Walter Roberson
el 30 de Mzo. de 2013
Editada: Walter Roberson
el 30 de Mzo. de 2013
Use sub2ind()
3 comentarios
Walter Roberson
el 30 de Mzo. de 2013
Oops, yes, I was concentrating on not putting an "s" in and so left out the "2" :(
Cedric
el 30 de Mzo. de 2013
I thought that you had forgotten the "s" and I ended up realizing that it was a "2" ;-)
Más respuestas (2)
Anand
el 30 de Mzo. de 2013
If A is your original matrix and idx is the matrix of indices, you can use logical indexing: A(idx).
Here's an example:
>> A = rand(3)
A =
0.8147 0.9134 0.2785
0.9058 0.6324 0.5469
0.1270 0.0975 0.9575
>> idx = [9 8 7;6 5 4;3 2 1]
idx =
9 8 7
6 5 4
3 2 1
>> A(idx)
ans =
0.9575 0.5469 0.2785
0.0975 0.6324 0.9134
0.1270 0.9058 0.8147
1 comentario
Ver también
Categorías
Más información sobre Matrix Indexing en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!