To Write a function called voltage that computes the voltages at different junctions in electrical circuit. after writing the program the output is not coming please help

8 visualizaciones (últimos 30 días)
function sol = voltage(V,R)
M =[R(2)*R(7)+R(1)*R(2)+R(1)*R(7),-R(1)*R(2),0;-R(3)*R(4)*R(8),R(4)*R(7)*R(8)+R(3)*R(4)*R(8)+R(3)*R(4)*R(7)+R(3)*R(7)*R(8),-R(3)*R(4)*R(7);0,-R(5)*R(6),R(6)*R(8)+R(5)*R(6)+R(5)*R(8)];
y =V*[R(2)*R(7);R(4)*R(7)*R(8);R(6)*R(8)];
SOL=M\y;
end

Respuestas (5)

Ritvij Sahasrabuddhe
Ritvij Sahasrabuddhe el 2 de En. de 2021
You have used 'sol' and 'SOL' as function def output, which are considered 2 different variables

PRASANTH R
PRASANTH R el 27 de Dic. de 2020

Anthony
Anthony el 1 de Mzo. de 2021
Editada: DGM el 4 de Mzo. de 2023
function sol = voltage(V,R)
M =[R(2)*R(7)+R(1)*R(2)+R(1)*R(7),-R(1)*R(2),0;
-R(3)*R(4)*R(8),R(4)*R(7)*R(8)+R(3)*R(4)*R(8)+R(3)*R(4)*R(7)+R(3)*R(7)*R(8),-R(3)*R(4)*R(7);
0,-R(5)*R(6),R(6)*R(8)+R(5)*R(6)+R(5)*R(8)];
y =V*[R(2)*R(7);R(4)*R(7)*R(8);R(6)*R(8)];
sol=M\y;
end

Tapan Chahar
Tapan Chahar el 15 de Mayo de 2022
Editada: DGM el 4 de Mzo. de 2023
function [X]=voltage(V,R)
% Writing equations about the 3 node points using Kirchoffs Law & rewritting
% them in terms of matrix we get
if R(1)==0||R(3)==0||R(5)==0
% When resistor R1 =0
if R(1)==0
A=[(1/R(3)+1/R(7)+1/R(8)+1/R(4)),(-1/R(8)) ; (-1/R(8)),(1/R(5)+1/R(8)+1/R(6))];
b=[(V/R(3)+V/R(7));V/R(5)];
XX=A\b;
X=[V;XX];
end
% When resistor R3 =0
if R(3)==0
A=[(1/R(1)+1/R(2)+1/R(7)),0 ; (-1/R(8)),(1/R(5)+1/R(8)+1/R(6))];
b=[(V/R(1)+V/R(7));V/R(5)];
XX=A\b;
X=[XX(1);V;XX(2)];
end
% When resistor R5 =0
if R(5)==0
A=[(1/R(1)+1/R(2)+1/R(7)),(-1/R(7)) ; (-1/R(7)),(1/R(3)+1/R(4)+1/R(7)+1/R(8))];
b=[V/R(1);V/R(3)+V/R(8)];
XX=A\b;
X=[XX;V];
end
% When both resistor R3 & R5 are =0
if R(3)==0&R(5)==0
A=[(1/R(1)+1/R(2)+1/R(7))];
b=[V/R(1)+V/R(7)];
XX=A\b;
X=[XX;V;V];
end
% When both resistor R1 & R3 are =0
if R(1)==0&R(3)==0
A=[(1/R(5)+1/R(6)+1/R(8))];
b=[V/R(5)+V/R(8)];
XX=A\b;
X=[V;V;XX];
end
% When both resistor R1 & R5 are =0
if R(1)==0&R(5)==0
A=[(1/R(3)+1/R(4)+1/R(7)+1/R(8))];
b=[V/R(3)+V/R(7)+V/R(8)];
XX=A\b;
X=[V;XX;V];
end
% When resistor R1, R3 & R5 are =0
if R(1)==0&R(3)==0&R(5)==0
X=[V;V;V];
end
% When resistor R1,R3 & R5 are non zero
else
A=[(1/R(1)+1/R(2)+1/R(7)),(-1/R(7)),0 ; (-1/R(7)),(1/R(3)+1/R(7)+1/R(8)+1/R(4)),(-1/R(8)) ; 0,(-1/R(8)),(1/R(5)+1/R(8)+1/R(6))];
b=[V/R(1);V/R(3);V/R(5)];
X=A\b;
end
end

Tapan Chahar
Tapan Chahar el 15 de Mayo de 2022
function X = voltage(V,R)
A = [ R(2)*R(7) + R(1)*R(2) + R(1)*R(7), -R(1)*R(2), 0;
-R(3)*R(4)*R(8), R(4)*R(7)*R(8) + R(3)*R(4)*R(8) + R(3)*R(4)*R(7) + R(3)*R(7)*R(8), -R(3)*R(4)*R(7);
0, -R(5)*R(6), R(6)*R(8) + R(5)*R(6) + R(5)*R(8) ];
b = V * [R(2)*R(7); R(4)*R(7)*R(8); R(6)*R(8)];
X = A \ b;
end

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