# Reading the matrix elements row wise

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Salahuddin Tariq on 30 Dec 2020
Commented: Salahuddin Tariq on 31 Dec 2020
Let say I have a matrix A = [1 2 3; 4 5 6], I can access its elements by writing A(1) and A(2) etc. but this index runs column wise. How to access elements of matrix row by row, for example if I write A(2), I want to get 2 and not 4.

Paul Hoffrichter on 31 Dec 2020
If you do not want to take the transpose of the A matrix, you can work with the subscripts instead.
A = [1 2 3; 4 5 6];
sz = size(A);
fiA = @(x) sub2ind(sz, ceil( x/sz(2) ), rem(x-1, sz(2)) + 1);
xx = 1:numel(A);
A(fiA(xx))
ans =
1 2 3 4 5 6
##### 2 CommentsShowHide 1 older comment
Salahuddin Tariq on 31 Dec 2020
Thanks for updating the other methods :) because I was aware that how to do it using the transponse matrix operation. Actually I wanted to avoid the usage of for loop while scanning the elements of matrix.

Paul Hoffrichter on 30 Dec 2020
Edited: Paul Hoffrichter on 30 Dec 2020
A = [1 2 3; 4 5 6];
Atr = transpose(A);
Atr(1:6)
ans =
1 2 3 4 5 6

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