Row and Cloumn find in cell array

f={[4,5];[6,8];7; 6;[];9;[8,9];[ ];[ ];[ ]}
ans=find([f{:}] == 6)
% ans= 3 6

I try this;

[row,col]=find([f{:}] == 6)

%row =

1 1

%col =

3 6

but I don't want this, 6 in f cell;

row/col; 2,1 and 4,1

Can u help me for this?

Answer 1

[Image Analyst]

Well here's one way.

f={[4,5];
	[6,8];
	7;
	6;
	[];
	9;
	[8,9];
	[ ];
	[ ];
	[ ]}
count = 1;
for k = 1 : length(f)
	has6 = find(f{k} == 6);
	if ~isempty(has6)
		locations{count} = [k, has6];
		count = count + 1;
	end
end
celldisp(locations)

Not very compact but it is intuitive. Someone will probably give you a one-liner using cellfun().

Answer 2

[Stephen23]

What you want is actually the cell index and the index of the cell content, not the "row and column" index as you wrote.

f = {[4,5];[6,8];7;6;[];9;[8,9];[];[];[]};
nml = cumsum(cellfun(@numel,f));
idx = find([f{:}]==6);
idr = 1+sum(nml<idx,1)

idr = 1×2

2 4

●

idc = idx(:)-nml(idr-1)

idc = 2×1

1 1

●