Legend function shows wrong colors.

2 visualizaciones (últimos 30 días)
Oguz Munib Esen
Oguz Munib Esen el 11 de En. de 2021
Editada: Oguz Munib Esen el 11 de En. de 2021
Hi, i want to plot my curves with respect to time. However legend function assigns wrong color values to wrong colors. That is, it does not name them with the order gave to it.
Thanks for the help!
clc
clear all
close all
k_a=1/8;
k_b=0.2;
k_c=4;
k_g=0.1;
k_w=0.2;
h=0.2;
ti=0;
tf=100;
T=ti:h:tf;
S=zeros(length(T));
E=zeros(length(T));
I=zeros(length(T));
M=zeros(length(T));
R=zeros(length(T));
%%Some code.
plot(T,S)
hold on
plot(T,E)
hold on
plot(T,I)
hold on
plot(T,M)
hold on
plot(T,R)
hold on
legend('Suceptibles','Exposed','Infected','Medicaly Semptomatic','Recovered')
  2 comentarios
Adam
Adam el 11 de En. de 2021
It would help if you posted the result of doing all that so we can see what the legend looks like. It seems fine to me when I run it.
Oguz Munib Esen
Oguz Munib Esen el 11 de En. de 2021
Thanks! Walter pointed out my mistake.

Iniciar sesión para comentar.

Respuesta aceptada

Walter Roberson
Walter Roberson el 11 de En. de 2021
zeros(length(T)) is the same as zeros(length(T), length(T)) which is a 2D array.
k_a=1/8;
k_b=0.2;
k_c=4;
k_g=0.1;
k_w=0.2;
h=0.2;
ti=0;
tf=100;
T=ti:h:tf;
S=zeros(size(T));
E=zeros(size(T));
I=zeros(size(T));
M=zeros(size(T));
R=zeros(size(T));
S(1)=10000;
E(1)=10;
I(1)=0;
M(1)=0;
R(1)=0;
for i=1:length(T)-1
S(i+1)=S(i)-h*((k_c*k_b*I(i)*S(i))/(S(i)+E(i)+I(i)+M(i)+R(i)));
E(i+1)=E(i)+h*((k_c*k_b*I(i)*S(i))/(S(i)+E(i)+I(i)+M(i)+R(i))-(k_a*E(i)));
I(i+1)=I(i)+h*((k_a*E(i))-(k_g*I(i)));
M(i+1)=M(i)+h*((k_g*I(i))-(k_w*M(i)));
R(i+1)=R(i)+h*((k_w*M(i)));
end
plot(T,S, 'b.-')
hold on
plot(T,E, 'k*-')
hold on
plot(T,I, 'r+-')
hold on
plot(T,M, 'c^-')
hold on
plot(T,R, 'gv-')
hold on
legend('Suceptibles','Exposed','Infected','Medicaly Semptomatic','Recovered')
  1 comentario
Oguz Munib Esen
Oguz Munib Esen el 11 de En. de 2021
Thank you, So my mistake was defining NxN matrices instead of 1xN vectors.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Legend en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by