Replacing empty cells using for loop
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Owen Gray
el 22 de En. de 2021
Comentada: Owen Gray
el 24 de En. de 2021
Hi there, I have 796x1 cell array consisting of 1x1 scalar arrays, or empty arrays. E.g.
>> ses1_results = {1.192;0;0;0;0.5678;0;0;0;0;0;0;1;[];1}
ses1_results =
14×1 cell array
{[ 1.1920]}
{[ 0]}
{[ 0]}
{[ 0]}
{[ 0.5678]}
{[ 0]}
{[ 0]}
{[ 0]}
{[ 0]}
{[ 0]}
{[ 0]}
{[ 1]}
{0×0 double}
{[ 1]}
The spacing of the 0s is irregular
I need to remove all the cells with 0, whilst maintaining the 0x0 cells and the values>0, and then convert that into an array. How can I do this? I've spent a few hours trying to do it like this but can't seem to figure it out:
Rxtcell = ses1_results(5:800,6);
for n = 1:796
Z = []
Q = 0
x = Rxtcell(n)
if 1 == strcmp(x,Q)
Rxtcell{n}=[999];
elseif 1== strcmp(x,Z)
Rxtcell(n)= [0];
else
end
end
RxTa = cell2mat(Rxtcell)
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dpb
el 22 de En. de 2021
Editada: dpb
el 23 de En. de 2021
Short answer is, "you can't".
A double array cannot have an empty element; it is either empty or full.
A cell array is the only way in which I see you can do this other than, perhaps you could cobble something together with sparse maybe???
The only alternative I see in an ordinary array would be to replace the empty cell with NaN or some other indicator value.
ses1_results{cellfun(@isempty,ses1_results)}=nan;
res=cell2mat(ses1_results);
res(res==0)=[];
returns
res =
1.1920
0.5678
1.0000
NaN
1.0000
>>
Or, of course, following the comment; you've already got a cell array; just remove the cells that are zero.
>> ses1_results(~cellfun(@(v)isequal(v,0),ses1_results))
ans =
5×1 cell array
{[ 1.1920]}
{[ 0.5678]}
{[ 1]}
{0×0 double}
{[ 1]}
>>
Más respuestas (1)
Walter Roberson
el 22 de En. de 2021
ses1_results = {1.192;0;0;0;0.5678;0;0;0;0;0;0;1;[];1}
mask = cellfun(@(C) numel(C) == 1 && C == 0, ses1_results);
rest = ses1_results(~mask)
However, your code suggests you want to do something different than that.
ses1_results = {1.192;0;0;0;0.5678;0;0;0;0;0;0;1;[];1}
mask0 = cellfun(@(C) numel(C) == 1 && C == 0, ses1_results);
maske = cellfun(@isempty, ses1_results);
Rtxcell = ses1_results;
Rtxcell(mask0) = {999};
Rtxcell(maske) = {0};
RxTa = cell2mat(Rtxcell)
2 comentarios
Walter Roberson
el 22 de En. de 2021
? I do not see any difference between what you posted in that comment and what you posted earlier?
ses1_results = {1.192;0;0;0;0.5678;0;0;0;0;0;0;1;[];1}
Note that numel(C) == 1 is not testing the content of an entry for value 1: it is testing whether there is exactly one entry in the cell. You see, you did not promise that each entry was either empty or had exactly one value in it. Your attempt to turn the cell into an array will fail if any cells have more than 1 entry in them, but that's a problem for later.
If you can promise that each entry is either empty or contains exactly one entry then you can replace
mask0 = cellfun(@(C) numel(C) == 1 && C == 0, ses1_results);
with
mask0 = cellfun(@(C) ~isempty(C) && C == 0, ses1_results);
which will fail during the cellfun() phase if there are any entries that have more than 1 value in them.
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