evaluate expression
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I have equation y=x*exp( (1-y)/(A*y)*B ) where A nd B constants in my program. I have a vector values for x. How can I evaluate y to plot y versus x ?
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Respuesta aceptada
Andrei Bobrov
el 12 de Mayo de 2011
ezplot(['y-x*exp( (1-y)/(' num2str(A) '*y)*' num2str(B) ')'],[x(1) x(end)])
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As = ...;
Bs = ...;
y = zeros(size(x));
for j = 1:length(x)
y(j) = fzero(@(y)y-x(j).*exp( (1-y)./(As*y)*Bs ),1);
end
plot(x,y);
2 comentarios
John D'Errico
el 12 de Mayo de 2011
It is generally not a good idea to convert the numeric values into strings to then pass into ezplot. This loses precision. Far, far better is to use an anonymous function here.
Más respuestas (1)
Andrew Newell
el 12 de Mayo de 2011
It would be simpler to provide y and solve for x:
y = -1:0.01:1;
x = y.*exp(- (1-y)./(A*y)*B );
In plotting this, you have to be careful because x goes to Inf or -Inf as y approaches zero from below:
I = y < 0 & abs(x) < 10;
plot(x(I),y(I))
hold on
I = y > 0 & abs(x) < 10;
plot(x(I),y(I))
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