evaluate expression

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omnia
omnia el 12 de Mayo de 2011
I have equation y=x*exp( (1-y)/(A*y)*B ) where A nd B constants in my program. I have a vector values for x. How can I evaluate y to plot y versus x ?

Respuesta aceptada

Andrei Bobrov
Andrei Bobrov el 12 de Mayo de 2011
ezplot(['y-x*exp( (1-y)/(' num2str(A) '*y)*' num2str(B) ')'],[x(1) x(end)])
more
As = ...;
Bs = ...;
y = zeros(size(x));
for j = 1:length(x)
y(j) = fzero(@(y)y-x(j).*exp( (1-y)./(As*y)*Bs ),1);
end
plot(x,y);
  2 comentarios
John D'Errico
John D'Errico el 12 de Mayo de 2011
It is generally not a good idea to convert the numeric values into strings to then pass into ezplot. This loses precision. Far, far better is to use an anonymous function here.
omnia
omnia el 13 de Mayo de 2011
Thank you alot

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Más respuestas (1)

Andrew Newell
Andrew Newell el 12 de Mayo de 2011
It would be simpler to provide y and solve for x:
y = -1:0.01:1;
x = y.*exp(- (1-y)./(A*y)*B );
In plotting this, you have to be careful because x goes to Inf or -Inf as y approaches zero from below:
I = y < 0 & abs(x) < 10;
plot(x(I),y(I))
hold on
I = y > 0 & abs(x) < 10;
plot(x(I),y(I))
  1 comentario
omnia
omnia el 13 de Mayo de 2011
yes I know it is easier to provide y and solve for x, but I don't have y. The input to my file is x values.

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