Convert an array of letters into numbers

I would like to convert an array of letters into numbers. Based on this code:
Alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
numbers = [3,6,12,1,1,3]
letters = Alphabet(numbers)
I would like to make the reverse of this. I mean I want to find eg 'HELLO' to which numbers correspont based on the above code.

Respuestas (2)

Alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
Alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
[~, HelloNumbers] = ismember('HELLO', Alphabet)
HelloNumbers = 1×5
8 5 12 12 15
Map(Alphabet) = 1:length(Alphabet);
Map('HELLO')
ans = 1×5
8 5 12 12 15

5 comentarios

Ivan Mich
Ivan Mich el 30 de En. de 2021
Thank you. One more question. Is there a way to "include" to Alphabet accents to letters (I mean à for example). I mean to regognize these accents and to give them one specific number?
Alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZÀÈÌÒÙÁÉÍÓÚÄËÏÖŸ';
Map(Alphabet) = 1:length(Alphabet);
Map('HÈLLÖ')
ans = 1×5
8 28 12 12 40
Ivan Mich
Ivan Mich el 31 de En. de 2021
Is there a way to set A equal to Á and À? I mean in order to not take into account accents?
Stephen23
Stephen23 el 31 de En. de 2021
"Is there a way to set A equal to Á and À? I mean in order to not take into account accents?"
Yes, two approaches were given to you in answers to your earlier question (which you then deleted):
Alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZÀÈÌÒÙÁÉÍÓÚÄËÏÖŸ';
Map(Alphabet(1:26)) = 1:26;
Map(Alphabet(27:end)) = Map('AEIOUAEIOUAEIOY');
Map('HÈLLÖ')
ans = 1×5
8 5 12 12 15

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Ive J
Ive J el 30 de En. de 2021
Editada: Ive J el 30 de En. de 2021
One way would be Map object:
alph = 'A':'Z';
num = 1:numel(alph); % or whatever
M = containers.Map(string(alph'), num);
term = 'HELLO';
arrayfun(@(x) M(x), string(term')).'
ans =
8 5 12 12 15

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el 30 de En. de 2021

Comentada:

el 31 de En. de 2021

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