Image registration with Gradient descent
5 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
I am trying to register two images based on gradient descent and sum square difference between two images. however, i have problem to update my transform matrix in each iteration. it can update translation but when i add rotation it just cant provide any correct results.
the following code is belongs to gradient descent with respect to translation and rotation:
[gy gx]=gradient(registerimage);
dx=sum(2*(gx(:)).*(referenceimage-registerimage(:)));
dy=sum(2*(gy(:)).*(referenceimage-registerimage(:)));
for i=1:128 (pixel position of registered image)
for j=1:128
Ir(i,j)=((-j)*gx(i,j))+(i*gy(i,j));
end
end
dr=sum(2*(Ir(:)).*(referenceimage-registerimage(:)));
after finding these gradient decent the following code has been used in order to update translation part of transform matrix:
trans(1,3)=trans(1,3)+currentStepSize*dx/lenght;
trans(2,3)=trans(2,3)+currentStepSize*dy/lengh
at the begining of program transform matrix defined as eye(3), current step size (learning rate of gradient) is define as 0.5 but it will increase or decrease by factor of 2 based on the results of each iteration
and length is:
lenght=sqrt(dx^2+dy^2);
Now i have problem to change trans(1,1),trans(1,2),trans(2,1) and trans(2,2) which are belong to rotation part. i will be glad to have your comments on it becuase i really stuck.
Thanks
2 comentarios
Sean de Wolski
el 12 de Mayo de 2011
Could you please reformat your post to make it readable. (See markup help)
Respuesta aceptada
Walter Roberson
el 12 de Mayo de 2011
Did you really code a variable named "lengh" and another named "lenght", both of which are confusingly close to the name of the built-in function "length" ?
1 comentario
Más respuestas (1)
Sean de Wolski
el 12 de Mayo de 2011
The for-loop can be vectorized with
Ir = bsxfun(@times,gx,-(1:128))+bsxfun(@times,gy,-(1:128).');
0 comentarios
Ver también
Categorías
Más información sobre Geometric Transformation and Image Registration en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!