How do you count how many values are in an array until a given number?

I have an array of values, it starts with integers then some zeros appear before finally more integers and then more zeros. I am looking to find a way to cut the array short before the second set of zeros appear.

The minimum value always occurs in column 5 of the second set of integers so I thought I could find the minimum value and cut if off there, however to do this I need to know how what row this minimum number occurs at. Ive seen in some forums that the find function may be able to be used however I cant get it to work. An extract of my script is posted below.

 data = csvread(['groupC0',num2str(i),'.CSV'],6,0);
 limit = find(data,min(data(:,5)))
 truedata = data(1:limit,3:8);

[Jan]

The text description of the inputs is not clear. Are you talking about a vector or a matrix? If it is a matrix, do the zero blocks have the same position in each row (or column?)?

Answer 1

[Jan]

x = [1,2,3,4,5,0,0,0,0,4,3,2,4,2,0,0,0,0,4,3,2];  % Does this match your data?!
zeroBlockStart = strfind(x == 0, [false, true]) + 1;

Now you have the indices, where the blocks of zeros start. Does this help already?

[Dave]

Thanks for your response, it was imported as a matrix but I was only looking for the maximum value in one column. I made it work by using:

    data = csvread(['groupC0',num2str(i),'.CSV'],6,0);
    [r minloc] = find(data==min(data(:,5)));
    truedata = data(1:r,3:8);