- for loop is unnecessary;
- Wrong way to index matrix u;
- t1 is unnecessary cause t1 have the same probability distributions with u;
loop with uniform distribution
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hasan s
el 3 de Feb. de 2021
Comentada: hasan s
el 11 de Feb. de 2021
Hi
Let u(i) is uniform distribution in (0,1), with size (1 column contain 10 number), and the values of u(i) is different in every loop.since the values of u(i) is random uniform distribution will take any values in (0,1).
I want
the RESULT of t3 must contain 15 column ,and every column contain 10 number, with the values of u(i) is different in every i=1:15
this is my try ,what I change to get the above RESULT.
thanks a lot for any help.
sz = [10 1];
a=1.778;
for i=1:15
u(i) = unifrnd(0,1,sz)
t1=1 - u(i);
t2=t1/a;
t3=exp(t2);
end
t3
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Respuesta aceptada
weikang zhao
el 4 de Feb. de 2021
you can get t3 by:
t3=exp(unifrnd(0,1/1.778,10,15));
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