Borrar filtros
Borrar filtros

How to solve Index out of bounds because numel(A)=4

1 visualización (últimos 30 días)
U B
U B el 12 de Feb. de 2021
Comentada: KSSV el 12 de Feb. de 2021
My aim is to generate the intensity profile for the output light passing through a polariser and an analyser for different angles of analyser . I am cosidering a gaussian light beam.
gaussian function-
function H = my_gaussian(n, sigma)
two_sigma_sq = 2*sigma*sigma;
H = zeros(n);
for i = 1:n
for j = 1:n
x = i - n/2;
y = j - n/2;
H(i,j) = exp(-(x*x + y*y)/two_sigma_sq);
end
end
end
Intensity profile-
H = my_gaussian(256, 50) ;
Ph = 0; E1 = cosd(Ph); E2 = sind(Ph);
E = [E1 ; E2];
Th = [0 30 90];
for i = 1:length(Th)
A11 = cosd(Th(i))*cosd(Th(i));
A12 = cosd(Th(i))*sind(Th(i));
A21 = cosd(Th(i))*sind(Th(i));
A22 = sind(Th(i))*sind(Th(i));
A = [A11, A12; A21, A22]
O = A(i)*E
I = O'*O
IP = I*H;
figure, imshow(IP);axis image;colorbar;
end
I can put maximum 3 values of Th, it gives me correct answer but as soon as I put 4 values, the 4th value is Incorrect. If I try putting more than 4 values error comes up saying
" Attempted to access A(5); index out of bounds because numel(A)=4.
Error in Untitled2 (line 31)
O = A(i)*E "
What should I change in this program?
  1 comentario
KSSV
KSSV el 12 de Feb. de 2021
What inputs you have tried? The given code now workd fine.

Iniciar sesión para comentar.

Respuesta aceptada

KSSV
KSSV el 12 de Feb. de 2021
This line:
O = A(i)*E ;
should be changed to:
O = A*E
  2 comentarios
U B
U B el 12 de Feb. de 2021
It worked. Thank you so much for your help.
KSSV
KSSV el 12 de Feb. de 2021
Thanks is accepting/ voting the aswer.. :)

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre MATLAB en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by