error in computing atanh

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Francisco Peñuñuri
Francisco Peñuñuri el 13 de Feb. de 2021
Editada: Francisco Peñuñuri el 13 de Feb. de 2021
When computing atanh(3.1) in R2018.a and R2020.a the complex part has positive sign.
When computing in fortran (and Mathematica) the result is negative.

Respuesta aceptada

David Goodmanson
David Goodmanson el 13 de Feb. de 2021
Editada: David Goodmanson el 13 de Feb. de 2021
Hello Francisco,
The imaginary part is i*pi/2, so the two answers are a+i*pi/2 and a-i*pi/2, where a is real. Both answers are equally valid, so unless an answer is violating some prearranged standard set by the particular software invoked, there is not an error. Note that
tanh(a+i*b) = tanh(a+i*b+i*n*pi)
so there is an ambiguity modulo i*pi in the atahh function..
  3 comentarios
John D'Errico
John D'Errico el 13 de Feb. de 2021
But there is no international standards commission that decides which is the principal branch to take on some multi-valued result. And while it seems pretty standard to take the POSITIVE branch for a sqrt, so it may have seemed just as logical to take the positive branch here.
The result is valid and non-unique. You cannot say more than that.
Francisco Peñuñuri
Francisco Peñuñuri el 13 de Feb. de 2021
Editada: Francisco Peñuñuri el 13 de Feb. de 2021
I agree with you. Still, is somehow awkward that sqrt(4) gives the principal value (regardless if this is positive or negative) while atanh(3.1) does not. I will accept the answer.
Thank you very much.

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