creating partition of sets
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
I am getting error, can anyone correct it please. Thanks in advance.
%A partition of a set A is a finite or infinite collection of nonempty, mutually disjoint subsets whose union is A.
A = [0, 1, 2, 3, 4]
C = {}; D = [];
j = 1;
while j < 10
P = input('Enter INTEGERS with [ ] around them');
D = cell2mat(C)
if ismember(P,A) == ones(1,length(P)) && ismember(P,D) ~= ones(1,length(D))
C{(end+1)} = P;
else
disp('Entered wrong, Please Enter correct one\n');
j = j;
end
j = j + 1;
end
0 comentarios
Respuestas (1)
Walter Roberson
el 16 de Feb. de 2021
if ismember(P,A) == ones(1,length(P)) && ismember(P,D) ~= ones(1,length(D))
P is a vector. ismember() is going to return a vector the same length. == comparison to ones is going to return a vector the same length. You cannot use && with vectors
You could perhaps replace the first test with
if all(ismember(P, A))
Your second test is harder to make sense of as your documentation does not make clear what you want to have happen if some entries match but others do not. I seem to be having difficulty translating your documentation as to what the program is intended to do or how it is intended to do it.
My guess:
if all(ismember(P, A)) && ~any(ismember(P, D))
1 comentario
Ver también
Categorías
Más información sobre Data Type Identification en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!