problem with the code

Hi,

Which angle is calculating with this matlab code

a=sensor1; b=sensor2; c=22;

numerator=(b^2)+(c^2)-(a^2); %Täljare demoninator=2*b*c; %Nämnare

cos_alpha=numerator/demoninator;

alpha=acosd(cos_alpha); %The angle alpha in degrees

Can anyone help me in understanding this code

Thanks in advance

[Jim]

The distance between sensors is c=22, a and b are the distance of the sensors from the object. Now which angle is being calculated with this code

Answer 1

[Roger Stafford]

Apparently there is a triangle with vertices A, B, and C with sides opposite to these vertices of length a, b, and c, resectively. The angle, alpha, at vertex A must satisfy the cosine law:

 a^2 = b^2 + c^2 - 2*b*c*cos(alpha)
 cos(alpha) = (b^2+c^2-a^2)/(2*b*c)
 alpha = acosd((b^2+c^2-a^2)/(2*b*c)) (in degrees)

[Jim]

Thanks for ur reply

After calculating the angle what the below command will do?

l=sind(alpha)*b;