Code is working:: However, Matrix obtained not correct (Code is working but the zeros elements place are not correct

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Hi all,
I need help in this code,
The Matrix obtained is correct however, the zeros elements are not in the correct place
Should be the following:
[164 54 0;
54 109 0;
0 0 109] ;
I think something is wrong in the indexing, but can not find ??
Below are the code:
clearvars;
clc;
close all;
E11 = 54;
E22 = 54;
v12 = .25;
v23 = .25;
S = zeros(9,9);
S(1,1) = 1/E11;
S(1,2) = -v12/E11;
S(1,3) = S(1,2);
S(2,1) = S(1,2);
S(2,2) = 1/E22;
S(2,3) = -v23/E22;
S(3,1) = S(1,2);
S(3,2) = S(2,3);
S(3,3) = 1/E22;
S(4,4) = (1+v12)/(E11);
S(5,5) = S(4,4);
S(6,6) = S(5,5);
S(7,7) = S(4,4);
S(8,8) = S(5,5);
S(9,9) = S(6,6);
C_n = inv(S);
C(1:3,1:3,1:3,1:3) = zeros(3,3,3,3);
IND =[1 1; 2 2; 3 3; 1 2; 2 3; 3 1; 2 1; 3 2; 1 3]
for m=1:9
for n=1:9
C(IND(m,1),IND(m,2),IND(n,1),IND(n,2)) = C_n(m,n);
end
end
t = 2.54;
delta = [1 1 1]*t;
A = zeros(3,3); % INITALIZATION OF A MATRIX
delAJ = [1 0 0]*(t*t);%permut(j,m,n)*delta(m)*delta(n);
for i = 1:3
for k = 1:3
for j = 1:3
for l = 1:3
A(i,k) = A(i,k) + delAJ(j)/delta(l)*C(i,j,k,l);
end
end
end
end
A
  10 comentarios
Cris LaPierre
Cris LaPierre el 3 de Mzo. de 2021
Editada: Cris LaPierre el 3 de Mzo. de 2021
I also played around with changing IND, as well as how you index C in your 4 nested for loops. The issue appears to be more than just a simple indexing issue, as a single change affects the entire output, not just a single value.
Without knowing what it is you are trying to implement, it's hard to determine where your code may be incorrect, especially as you noted, it's working. Could you share details on how S should be created, and what algorithm you are following to create C and to compute A?
Please assume that we are unfamiliar with the actual system you are solving. If you make it easy for us to understand what your code is supposed to be doing, we can probably be of more help.
Mark Sc
Mark Sc el 3 de Mzo. de 2021
Thanks for your reply..
I totally understand what point of view,
Next time, I will try to explain or comment what am I doing
Thanks again

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