Generating random numbers within a range determined by elements in another array
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Hello,
I was wondering if there is an efficient way to generate a random integer within a range depending on an element in another array. Perhaps a small example will explain better:
1 must generate a random number in [3 7];
2 must generate a random number in [1 3];
3 must generate a random number in [44 66]
So for the vector [3 1 2] I would want to get another vector [59 4 2], for example.
I was thinking of using arrayfun to do this but I don't know if there is a more efficient way?
Any help/advice would be greatly appreciated.
Thanks
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Iain
el 21 de Mayo de 2013
Editada: Andrei Bobrov
el 22 de Mayo de 2013
Array = [3 7; 1 3; 44 66];
Choose your row, "i"
NewRandom = roundingfunctionofchoice(rand(size(i)).*(Array(i,2)-Array(i,1)) + Array(i,1));
If you set i = [3 1 2], you'll get what you want.
Más respuestas (1)
Image Analyst
el 21 de Mayo de 2013
Did you look at the help for rand() and notice the first example? Here it is:
Example 1
Generate values from the uniform distribution on the interval [a, b]:
r = a + (b-a).*rand(100,1);
Basically it all comes down to that. Do that 3 times with different a and b depending on what the 3 numbers are. Is this homework?
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