Locating point on x-axis where the slope is decreasing

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Tessa Kol
Tessa Kol el 10 de Mzo. de 2021
Comentada: Star Strider el 10 de Mzo. de 2021
Dear all,
I used the following code to plot the angle over time:
figure
hold on
grid on
plot(Time, theta,'linewidth',1.5)
xlabel('Time [s]','FontWeight','bold')
ylabel('\theta [deg]','FontWeight','bold')
xlim([0 round(Time(end))])
legend('Opening angle','Location','northeast')
title('Opening angle')
The resulting graph is shown below. I want to index at what time the slope is decreasing. How can I do that?
The variables Time and theta to plot this graph can be found in the data.mat file.

Respuesta aceptada

Star Strider
Star Strider el 10 de Mzo. de 2021
A reasonably robust way is to use the ischange function:
D = load('data.mat');
Time = D.Time;
theta = D.theta;
[TF,m,b] = ischange(theta, 'linear', 'Threshold',5);
chgpts = [find(TF); m(TF); b(TF)].';
chgidx = find(chgpts(:,2)<0,1);
figure
plot(Time, theta,'linewidth',1.5)
hold on
plot(Time(chgpts(chgidx(:,1))), theta(chgpts(chgidx(:,1))), 'xr')
hold off
grid on
xlabel('Time [s]','FontWeight','bold')
ylabel('\theta [deg]','FontWeight','bold')
xlim([0 round(Time(end))])
legend('Opening angle','Location','northeast')
title('Opening angle')
producing:
The ‘Time’ value is then:
ChangePointTime = Time(chgpts(chgidx(:,1)));
that here is 6.01 seconds.
  4 comentarios
Tessa Kol
Tessa Kol el 10 de Mzo. de 2021
Thank you so much for the code and explanation!
Star Strider
Star Strider el 10 de Mzo. de 2021
As always, my pleasure!

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Más respuestas (1)

Sargondjani
Sargondjani el 10 de Mzo. de 2021
Bascially you want to get the index when the change in theta becomes negative:
dtheta = diff(theta);
index = find(dtheta<0,1);%the 1 refers to the first entry where the statement is true

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