not enough input arguments Error

Dear Colleagues and Teachers,

I am eperiencing a code error aginst this code ;

% Function to generate a multi-step custom membership function

% using 8 parameters for the input argument x

function out = custmf1(x,params)

for i = 1:length(x)

if x(i) < params(1)

y(i) = params(1);

elseif x(i) < params(2)

y(i) = params(2);

elseif x(i) < params(3)

y(i) = params(3);

elseif x(i) < params(4)

y(i) = params(4);

elseif x(i) < params(5)

y(i) = params(5);

elseif x(i) < params(6)

y(i) = params(6);

elseif x(i) < params(7)

y(i) = params(7);

elseif x(i) < params(8)

y(i) = params(8);

else

y(i) = 0;

end

end

out = 0.1*y'; % Scale the output to lie between 0 and 1.

end

Can anyone please tell me that how can i remove this error

-----------------------------

Command Window

>>custmf1

Error using custmf1 (line 3)

Not enough input arguments

Answer 1

[Star Strider]

Call it as:

out = custmf1(x,params);

with the arguments stated and in the calling script workspace. Only anonymous functions inherit existing workspace variables. Other functions do not.

[Asif Rashid]

Thankyou sir,

in the command window, when i write

>>out = custmf1(x,params);

i am getting an error

Undefined function or variable 'x'

Do you know how to solve this error as well please. Thankyou Sir

[Star Strider]

As always, my pleasure!

Both ‘x’ and ‘params’ must be present in your workspace before you call the function with those arguments.

[Asif Rashid]

ok sir . i got the point and and the problem is solved. Best wishes Sir.

but i have another question if you can help me to understand this in case if you know this. so , my question is about if loop.

i want to write

if NL is between 0.1 and 0.3 then output is NL

else if

NS is between 0.31 and 0.5 then output is NS

i just want to know the structure of this kind of if loop

Looking forward for your kindness please. Thankyou Sir

[Star Strider]

As always, my pleasure!

I am not certain what you want or how it relates to ‘x’ and ‘params’.

One way might be:

f = @(x,NS,NL) ((x>=0.1) & (x<=0.3)).*NL + ((x>0.3) & (x<=0.5)).*NS;

That is how I usually write such conditional statements, avoiding loops and if blocks.

[Asif Rashid]

i just got back to your kind reply and i got some idea about this statement .

if you can see another question , there the problem statement is for five conditions so can you please comment in that case please. i just ant to execute those 5 statements , please

in the end , i am very oblidged with your kind reply. thankyou and best wishes

[Star Strider]

I did, actually, citing my previous Comment here as an example.