If statement indexing in a for loop

I have made a for loop which models energy going being stored every hour. Three times a day energy is removed from storage. so far so good. I want to be able to check if the energy stored reaches a minimum value in the hour before energy is removed and if it does not then to add suffcient energy to reach the minimum value and record how much has been added. I'm trying to use an IF statement to interact with three columns in my matrix but am unable to make it work, it seems within the for loop my matrix becomes a vector? How can I isolate my three columns?

[Cris LaPierre]

Share your code.

[Calum Mackenzie]

restored = transpose(reshape(stored,24,92));

reavlesuse = transpose(reshape(avlesuse,24,92));

topupstored = zeros(92,24);

for i = 2:numel(restored);

if topupstored(i) % is in columb 7,12 or 16

% if topupstored(i) < min then find min - topupstored(i) and add to topupstored(i)

% else

% else

topupstored(i) = restored(i-1) + reavlesuse(i);

end

topupstored(i) = max(min(restored(i), ub), lb);

end

[Calum Mackenzie]

Sorry not sure how to upload vairables, I've added the comments to try and express what I want to achieve.

[Calum Mackenzie]

Hopefully this better explains what I'm trying to do

[Cris LaPierre]

Save your variables to a mat file and attache the mat file using the paperclip icon.

Answer 1

[Cris LaPierre]

I would do this without a for loop.

• Compute min-columns 7,12,16
• Set any values <0 to 0 (you don't have to add to these rows to reach the minimum)
• Add the result to the previous hour (column?)

[Calum Mackenzie]

I don't think this will work since the energy stored is dependant on the previous hour. So if I add 'top up' energy the first time there is a shortfall, that extra energy will be carried forwards to subsequent hours and likley reduce and may eliminate subsiquent shortfalls. Thats why i think it needs to be done sequentially in a loop?

[Cris LaPierre]

Ok, so add it to columns (7:end) the first time, etc.

You are going to understand the problem better than any of us. We can only operate on the information you've shared.