Problems using "datetime" cont.

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Andy Wileman
Andy Wileman el 17 de Mzo. de 2021
Comentada: Andy Wileman el 17 de Mzo. de 2021
Hi,
Having solved problems with getting the current date from a structure into a table (thank you Adam). Using "datetime" still does not seem to be carrying out the conversion. Any thoughts?
Kind regards,
Andy
table
Dates
_________________________________
"12/24/2008 9:59:47 AM.786743640"
%Current file format{'12/24/2008 9:59:47 AM.786743640'}
%Fileformat to convert to = data-20130325T004512Z.mat
date=cell2mat(dateName);
data=cell2mat(timeDom);
N = date
T = table(string(N), 'VariableNames', {'Dates'})
dt = datetime('T.Dates','Format','yyyyMMdd''T''HHmmss''Z')
% TODO: Save files
save(data, '-append', '-struct', 'dt');
Error using datetime (line 640)
Unable to convert 'T.Dates' to datetime using the format 'yyyyMMdd'T'HHmmss'Z'.
Error in extractor (line 20)
dt = datetime('T.Dates','Format','yyyyMMdd''T''HHmmss''Z')

Respuesta aceptada

Stephen23
Stephen23 el 17 de Mzo. de 2021
Editada: Stephen23 el 17 de Mzo. de 2021
You should probably specify the input format to match the provided string:
S = "12/24/2008 9:59:47 AM.786743640";
D = datetime(S, 'InputFormat','MM/dd/yyyy h:m:s a.SSSSSSSSS')
D = datetime
24-Dec-2008 09:59:47
D.Format = 'yyyyMMdd''T''HHmmss''Z'''
D = datetime
20081224T095947Z
You also need to refer to the table, not define a literal character vector:
datetime( T.Dates ,...) % correct way to refert to table T.
datetime('T.Dates',...) % defines a character vector, does not help you.
  3 comentarios
Stephen23
Stephen23 el 17 de Mzo. de 2021
@Andy Wileman: note that I assumed that the trailing decimal fraction are fractional seconds. If they represent some other data, then you will need to make the required changes.
Andy Wileman
Andy Wileman el 17 de Mzo. de 2021
I think they are trailing seconds, as the data is from data aquisition. Once again, thanks.

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