Getting a increasing by the nxn matrix inside a for loop

HI there i dont quite understand how to get a matrix that is increasing by nxn matrix

like for example

n=100

for i=1:n

matrixA=[1x1] matrix

iter1

matrixA=[2x2] matrix

iter 2

and so on until the 100x100 matrix, so

end

it would also help if the matrix i get can be used for the diag function?

Help is appreciated thank you in advance

Answer 1

[KSSV]

n=100 ;
matrixA = cell(n,1) ; 
for i=1:n
    matrixA{i} = rand(n) ;
end

[Mark Loui]

Hi could you please further explain a bit on the code please?

[Mark Loui]

And how can it be implemented into the diag function, or creating a diagonal matrix?

[Mark Loui]

Also i have run your code, from the output there is still a 0x0 matrix at the bottom there, hence it is not possible for me to go on with the next step, any other method you could recommend?

[KSSV]

Read about rand, it is used to create a random numbers.

To get diaogonal matrices...read about diag.

[Mark Loui]

Ok then can i ask how to fill up the matrix with any values

[KSSV]

That any is random....

n=100 ;
matrixA = cell(n,1) ; 
for i=1:n
    matrixA{i} = rand*diag(repmat(i,1,i)) ;
end