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want to reag .pgm images in matlab but get an error index exceeds matrix dimension

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divya
divya el 2 de Jun. de 2013
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
imwrite(imread('divya.pgm'),'C:\Users\div\Desktop\myfirstimage.jpg')
i am using this to read a pgm file..but i get an error index exceeds matrix dimention.please help

Respuestas (1)

Image Analyst
Image Analyst el 2 de Jun. de 2013
Let's break it down so we can see where the error is coming from:
originalImage = imread('divya.pgm')
imshow(originalImage);
imwrite(originalImage,'C:\Users\div\Desktop\myfirstimage.jpg')
Now what happens? Paste all the red error message text - don't paraphrase or cut anything.
  2 comentarios
divya
divya el 2 de Jun. de 2013
Index exceeds matrix dimensions.
Error in createLightSource (line 26)
G = round(sin(phi) * sum(sum(image(up:down,left:right,2))));
Error in cut (line 139)
createLightSource(cImage, left1, right1, up1, down1, r, n, m);
Error in cut (line 130)
cImage = cut(cImage, gsImage, left1, right1, up1, down1, n_now+1, n, r, m);
Error in cut (line 130)
cImage = cut(cImage, gsImage, left1, right1, up1, down1, n_now+1, n, r, m);
Error in varianceCut (line 50)
output = cut(input, greyscaleImage, left, right, up, down, 1, n, r, m); Error in program (line 74)
cutImage = varianceCut( rgb, n, r, m);
Image Analyst
Image Analyst el 2 de Jun. de 2013
Wow - that's really bizarre. That doesn't look anything like your original code, or my code. Are createLightSource(), cut(), and varianceCut() your functions? Or something from some toolbox?
One thing that looks weird is:
G = round(sin(phi) * sum(sum(image(up:down,left:right,2))));
image() is a built in function that takes an image variable and displays it. It's probably getting confused when you pass it two 2-element arrays and a scalar (2). You don't have an image anywhere in your code that you gave the name "image" to, do you? That would be bad. If you do, call your variable something else, like grayImage, originalImage, croppedImage, rgbImage, or something, anything, other than "image".

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