Get result from uitable's row number

I have uitable below and i wanna get results uitable's row number not matrix's row number.

f = figure('Position',[10 10 600 600]);

dat = {-1,1,1;0,-1,0;0,0,-1;1,0,0};

cnames = {'12','23','25'};

rnames = {'11','12','23','14'};

t = uitable('Parent',f,'Data',dat,'ColumnName',cnames,... 
            'RowName',rnames,'Position',[10 10 590 590]);

blnA = logical( A == -1 );

blnOut = find(any(A == -1,2));

max(blnOut)

ans =

       3

My expected result is 23 not 3. How can i get that value?

[Walter Roberson]

You have not defined "A"

[Light]

A=[-1,1,1;0,-1,0;0,0,-1;1,0,0];

I confused i think my workspace kept that A matrix and result is 3.

Anyway, how can i get value 23. I will not use A matrix i will use it in uitable

dat = {-1,1,1;0,-1,0;0,0,-1;1,0,0};

What will i do?

Answer 1

[Walter Roberson]

rnames are not a row number: rnames are row labels. You find the row number (a numeric value) but somehow you expect a string that is the row label to be returned by max() . max() never returns strings.

rnames{blnOut}

will give you the row label associated with the row #blnOut

[Light]

rnames{blnOut}

ans =

01

ans =

12

ans =

23

That 3 results occurred. How can i pick that result only 23 which refer to row 3

[Walter Roberson]

rnames{max(blnOut)}

[Light]

I'm again

f = figure('Position',[10 10 600 600]);

dat = {-1,1,1;0,-1,0;0,0,-1;1,0,0};

cnames = {'1','2','5'};

rnames = {'1','2','3','4'};

t = uitable('Parent',f,'Data',dat,'ColumnName',cnames,... 'RowName',rnames,'Position',[10 10 590 590]);

      blnA = logical( A == -1 );

blnOut = find(any(A == -1,2));

rnames{max(blnOut)};

negcolumn = find(A(min(blnOut),:) == 1);

cnames{max(negcolumn)};

dU(5)=7;

dU(cnames{max(negcolumn)})

Error message occurred. I couldn't find the mistake.(cnames{max(negcolumn)})=5 So it must be dU(5)=7 but error Index exceeds matrix dimensions.

[Image Analyst]

See my answer in your duplicate question: http://www.mathworks.com/matlabcentral/answers/78442#answer_88166