What am I doing wrong here? I am trying to recreate following highlighted equations in the table.

1 visualización (últimos 30 días)
ep = linspace(0,1);
m1 = 1.5; m2 = 3.8;
ep0= 1; alpha = 0.785; epp = 0.11;
qep = (2.76*ep*cosh((3*ep)-1.92));
I1 = ep.^ m1;
I2 = ep.^ m2;
I3 = ep*((ep-epp)/(ep0-epp)).^alpha;
I6 = 1-(qep*((3*(1-ep))/(3-ep)));
Hold on
plot(ep,I1)
plot(ep,I2)
plot(ep,I3)
plot(ep,I6)
Hold off

Respuesta aceptada

Paul Hoffrichter
Paul Hoffrichter el 27 de Mzo. de 2021
Editada: Paul Hoffrichter el 27 de Mzo. de 2021
clc; clear; clf
ep = linspace(0,1);
m1 = 1.5; m2 = 3.8;
ep0= 1; alpha = 0.785; epp = 0.11;
qep = (2.76*ep.*cosh((3*ep)-1.92));
I1 = ep.^ m1;
I2 = ep.^ m2;
zz = (ep-epp)/(ep0-epp);
zza = zz .^ alpha; % zza is complex
I3 = ep .* zza;
I6 = 1-(qep*((3*(1-ep))/(3-ep)));
hold on
plot(ep,I1);
plot(ep,I2)
plot(ep,I3) % This is Line 18 - usually do not plot a complex vector like this
plot(ep,I6)
hold off
warning:
Warning: Imaginary parts of complex X and/or Y arguments ignored.
> In Untitled (line 18)
  4 comentarios
Nissal Arachchige
Nissal Arachchige el 27 de Mzo. de 2021
No not at all. I was actually able to recognize my coading problem before you posted the answer and I got the same solution as you and the warning as well. I do not know why it does that. And I was supposed to recreate the follwing graph but ignore the points and the legend. I'm waiting for the feedback from my professor. I'll let you know if something intresting come up. Thanks again.
Paul Hoffrichter
Paul Hoffrichter el 28 de Mzo. de 2021
I was a surprised at first about the complex numbers. But then I thought about what if alpha was 0.5 instead of 0.785. Then if x is a negative number, we have a purely imaginary result for x^(.5)=sqrt(x)= sqrt{(-1) * abs(x)} = 0 + j*sqrt(abs(x)). For other values of alpha between (0.5, 1.0), we get complex numbers.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre MATLAB en Help Center y File Exchange.

Etiquetas

Productos


Versión

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by