fprintf: Function is not defined for 'cell' inputs.

Can someone say what is wrong with my code?

the errors are: *??? Error using ==> fprintf Function is not defined for 'cell' inputs.

Error in ==> TESTAR at 37 fprintf('Problem statement:\n%s', problem_statement);*

my code is:

clear; run('..\psg_load_libraries'); addpath('..');

clear problem_statement;

problem_statement(1)= textread('problem_DEA_Hospital.txt','%s', 'whitespace', ''); problem_statement(2)= textread('problem_DEA_Hospital2.txt','%s', 'whitespace', '');

% read and print problem statement

for i=1:1:2

    problem_statement=problem_statement(i);

fprintf('Problem statement:\n%s', problem_statement);

end

Answer 1

[Kalyne]

Hey Evan, Thanks for you answer.. I tryed to change it but it keeps given me the same message. the new code is like that:

clear problem_statement;

problem{1}= textread('problem_DEA_Hospital.txt','%s', 'whitespace', ''); problem{2}= textread('problem_DEA_Hospital2.txt','%s', 'whitespace', '');

% read and print problem statement

for i=1:1:2

    problem_statement=problem{i};

fprintf('Problem statement:\n%s', problem_statement);

[Evan]

Whenever you call textread, try changing problem{1} back to problem(1). Same thing for problem{2}.

Because () accesses the cell and {} accesses the contents of a cell, if textread returns a cell and you're putting it in the contents of another cell, that means you're getting a cell inside a cell. So even though you remove the contents of the cell for your variable that you use in fprintf, there's still one more "layer" of cell there that's tripping up the code.

[Evan]

Actually, I just thought about it, and either way a cell array will be returned. You might have to convert problem_statement to a character array when using fprintf even after accessing the contents of problem.

clear problem_statement;

problem{1} = textread('problem_DEA_Hospital.txt','%s', 'whitespace', ''); problem{2} = textread('problem_DEA_Hospital2.txt','%s', 'whitespace', '');

% read and print problem statement

for i = 1:2
   problem_statement = char(problem{i});
fprintf('Problem statement:\n%s', problem_statement);

Sorry about the confusion. I don't use textscan very much didn't consider the way it returned data. Hopefully that solves it.

Answer 2

[Evan]

It sounds like "problem_statement" is a cell array, and fprintf cannot accept cells as arguments. What if you change the second to last line to this:

problem_statement=problem_statement{i};

That will cause your new definition of "problem_statement" to access the contents of the ith cell of the problem_statement cell array instead of the ith cell itself.

Note, though, that I don't think the second iteration of your code will run correctly if you're redefining problem_statement as a single-element array before trying to later access the second element. You might want to give problem_statement a different name in the loop instead of redefining it.