# Count EVEN and ODD numbers

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Jan Vergel De Ocampo on 6 Apr 2021
Commented: KSSV on 6 Apr 2021
I have a problem where i needed to identify 5 input number whether they are EVEN or ODD which I am able to do. The problem is I needed the Total Count of the EVEN and ODD which is the thing that I do not know.
This is the code for inputs. I just need the code for the Total Count.
a = input("Please enter 1st number: ");
if mod(a,2)==0
disp("The 1st number is EVEN");
else
disp("The 1st number is ODD");
end
b = input("Please enter 2nd number: ");
if mod(b,2)==0
disp("The 2nd number is EVEN");
else
disp("The 2nd number is ODD");
end
c = input("Please enter 3rd number: ");
if mod(c,2)==0
disp("The 3rd number is EVEN");
else
disp("The 3rd number is ODD");
end
d = input("Please enter 4th number: ");
if mod(d,2)==0
disp("The 4th number is EVEN");
else
disp("The 4th number is ODD");
end
e = input("Please enter 5th number: ");
if mod(e,2)==0
disp("The 5th number is EVEN");
else
disp("The 5th number is ODD");
end

KSSV on 6 Apr 2021
clc; clear all ;
a = input("Please enter 1st number: ");
nE = 0 ; nO = 0 ;
if mod(a,2)==0
disp("The 1st number is EVEN");
nE = nE+1 ;
else
disp("The 1st number is ODD");
nO = nO+1 ;
end
b = input("Please enter 2nd number: ");
if mod(b,2)==0
disp("The 2nd number is EVEN");
nE = nE+1 ;
else
disp("The 2nd number is ODD");
nO = nO+1 ;
end
c = input("Please enter 3rd number: ");
if mod(c,2)==0
disp("The 3rd number is EVEN");
nE = nE+1 ;
else
disp("The 3rd number is ODD");
nO = nO+1 ;
end
d = input("Please enter 4th number: ");
if mod(d,2)==0
disp("The 4th number is EVEN");
nE = nE+1 ;
else
disp("The 4th number is ODD");
nO = nO+1 ;
end
e = input("Please enter 5th number: ");
if mod(e,2)==0
disp("The 5th number is EVEN");
nE = nE+1 ;
else
disp("The 5th number is ODD");
nO = nO+1 ;
end
fprintf('there are %d number of Even Numbers\n',nE)
fprintf('there are %d number of Odd Numbers\n',nO)
##### 2 CommentsShowHide 1 older comment
KSSV on 6 Apr 2021
Thanks is accepting/ voting the answer :)