convert image matrix to row vector

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Samaa Yasser
Samaa Yasser el 7 de Abr. de 2021
Comentada: Samaa Yasser el 8 de Abr. de 2021
i have an image size 256x256 and i want to Convert the image matrix to a row vector with length same size , how i can got it please?
  2 comentarios
DGM
DGM el 7 de Abr. de 2021
What exactly do you mean by "length of same size". Length isn't size.
You can use reshape() to reshape the array, but it will be [1 65536].
A=reshape(A',1,[]); % if you want rows
If you're expecting a [1 256] vector, then you'll have to decide how exactly you want to reduce the image conceptually (e.g. maybe you want directional mean or min or max; maybe you just want to extract a single row from the image)
Samaa Yasser
Samaa Yasser el 7 de Abr. de 2021
first thank you for your help..
i want to generate a row vector from image pixel.
so i want to calculate the total number of the original image pixels first, then Convert the image matrix of size MN for example to a row vector with length NM , inorder to get random permutation of this row vector, so can you help

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Respuestas (2)

David Hill
David Hill el 7 de Abr. de 2021
yourMatrix(:)';

DGM
DGM el 7 de Abr. de 2021
Editada: DGM el 7 de Abr. de 2021
Consider a 3x3 test image:
A=repmat(1:3,[3 1])
A =
1 2 3
1 2 3
1 2 3
The line I suggested:
A=reshape(A',1,[]); % if you want to sample from rows
will take the rows of A and end-concatenate them into one long row vector of size 1x9. No need to calculate numel(A).
A =
1 2 3 1 2 3 1 2 3
If instead you were to do
A=reshape(A,1,[]); % if you want to sample from cols
or
A=A(:)'; % David's suggestion
you would still get the same output size, but you would be sampling columnwise instead.
ans =
1 1 1 2 2 2 3 3 3
If the ordering of the pixels doesn't matter, you could do it either way.
  1 comentario
Samaa Yasser
Samaa Yasser el 8 de Abr. de 2021
thaaank you sooo much i really apperciate =)

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