Matlab integration of numerical data

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Sib RV
Sib RV el 8 de Abr. de 2021
Comentada: Sib RV el 8 de Abr. de 2021
I have numerical data for function f, calculated for a vector x (not a defined function of x). Can I create a functional form out of this so that I can use something like f(y) in further calculations and integrals ?
x = 0:1:10; F is calculated for eac x. Example : Want to integrate f(x+c) between some limits, (not 0,10) and for any constant c.

Respuestas (2)

Star Strider
Star Strider el 8 de Abr. de 2021
The cumtrapz funciton will likely do what you want, although I am not certain what result you want.

John D'Errico
John D'Errico el 8 de Abr. de 2021
Editada: John D'Errico el 8 de Abr. de 2021
In order for it to be truly general, you will need to interpolate the "function". For example, we might do this:
x = 0:10;
y = sin(x); % some function
Now, we wish to integrate y, but only based on the values we have generated. Remember that integrating beyond the linits of our data will be bad idea, because then we are forced to extrapolate the function. And THAT is a bad idea, unless our extrapolant is one chosen carefully. A spline will be a terribly poor tool to extrapolate.
f = spline(x,y);
fint = fnint(f); % this lives in the curve fitting toolbox.
Now, assume we wish the integral of y, between x and x + c. In this example, I'll use x=0.1223, and c=4.75.
fintxc = @(x,c) fnval(fint,x+c) - fnval(fint,x);
fintxc(0.1223,4.75)
ans = 0.8435
How well did we do? Remember, this can be no more than an approximation. We can use integral on the original function to do the work, although I could be more intelligent, since I know the integral of the sine function. I'll take the lazy way here.
integral(@sin,0.1223,0.1223 + 4.75)
ans = 0.8333
Which given the coarseness of the original sample, is not at all bad.
  3 comentarios
John D'Errico
John D'Errico el 8 de Abr. de 2021
It depends on how nasty is the function, and how densely sampled. Interpolation can be very well behaved. No, you probably don't want to do linear interpolation, but you could, and it would provide an integratino estimate that is essentially equivalent to a trapezoidal rule.
That is why a spline is a good choice, since it is effectively a higher orer interpolant. Or you might want to use a shape preserving interpolant, like pchip. Finally, you could even use a tool like my SLM toolbox, which can produce spline interpolants that will be well-behaved.
Sib RV
Sib RV el 8 de Abr. de 2021
Thank you.

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