Input #2 expected to be a cell array, was struct instead.
13 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Darshan Gade
el 14 de Abr. de 2021
Respondida: Walter Roberson
el 14 de Abr. de 2021
Can anyone tell what is the issue here
>> {MISRAErrorTables(fl).Table(tl).Line}
ans =
1×1 cell array
{'29'}
>> x = Code2Model
x =
struct with fields:
token: [1×1 struct]
file: [1×1 struct]
line: [1×1 struct]
begin: [1×1 struct]
sidlink: [1×1 struct]
>> {x.line.Text}
ans =
1×1 cell array
{'29'}
>> {x.file.Text}
ans =
1×1 cell array
{'Generic20kHzModule_ac.c'}
>> {[ModelName,'_ac.c']}
ans =
1×1 cell array
{'Generic20kHzModule_ac.c'}
>> LineIndex{tl} = find(cell2mat(cellfun(@(x)(strcmp({x.line.Text},{MISRAErrorTables(fl).Table(tl).Line})...
&& strcmp({x.file.Text},{[ModelName,'_ac.c']})),Code2Model,'UniformOutput',false)))
Error using cellfun
Input #2 expected to be a cell array, was struct instead.
1 comentario
Daniel Pollard
el 14 de Abr. de 2021
Please format your code properly. Explain what the code does and how you expected it to work. I tried reading through what's there but it makes no sense to someone who's not you, and we can't run it because you haven't defined any of the variables.
As it happens, "Input #2 expected to be a cell array, was struct instead." is a very descriptive error message. The function expected the second input to be a cell array. You gave it a structure instead. The code errored. Since you don't explain the code, the inputs or the expected outputs, no one can help you.
Respuesta aceptada
Walter Roberson
el 14 de Abr. de 2021
You need arrayfun() instead of cellfun() for that purpose.
This assumes that in time Code2Model will be a non-scalar struct array.
0 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Structures en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!