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standard deviation of two elements of a 3d matrix

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William
William el 28 de Jun. de 2013
Greetings,
I have a 672 x 32 x 2800 matrix that I need to chop into a 672 x 2800 matrix but the rows need to be the standard deviation of the columns in the original 3d matrix. Here is what I am doing which is all wrong
new_col_data = zeros(672,2800);
new_col_data = [std(data, 0, 2),:]
I cannot figure this out. Can someone please tell me what is wrong?
Thank you

Respuesta aceptada

Shashank Prasanna
Shashank Prasanna el 28 de Jun. de 2013
Editada: Shashank Prasanna el 28 de Jun. de 2013
A = rand(672,32,2800); % Some random data:
B = std(A,[],2); % Compute the standard deviation
B = squeeze(B); % Squeeze it

Más respuestas (2)

Sean de Wolski
Sean de Wolski el 28 de Jun. de 2013
Sounds like you want to squeeze it!
squeeze(std(rand(60,30,45),0,2))

William
William el 28 de Jun. de 2013
I tried this:
>> new_col_data = squeeze(std(data,0,2),:);
Error using var (line 59)
First argument must be single or double.
Error in std (line 32)
Something went wrong. I do not have a single dimension in this matrix
  1 comentario
Sean de Wolski
Sean de Wolski el 28 de Jun. de 2013
Mine doesn't have a squeeze(blah,:). It's supposed to jsut be squeeze(blah)

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