Obviously switch case can be used to display valid for 1:10 but it will break the code if any other input is entered.
Incremental conditions for if statement
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Louis Grainger
el 22 de Abr. de 2021
Respondida: Steven Lord
el 22 de Abr. de 2021
I'm trying to return an invalid message for any value not inside the parameters.
Given this for loop with an embedded while and if just to check the inputs value.
for i = 1:2
fprintf("iteration %d\n", i);
flag = 1;
while flag == 1
row = input(":");
if row ~= 1
fprintf("invalid input\n");
fprintf("while restarts\n");
flag = 1;
else
fprintf("valid input\n");
flag = 0;
end
end
fprintf("while ends\n");
end
fprintf("end\n");
Is there a way to implement a if row ~= 1:10 condition?
Alternativley is there a way to use switch cases?
Respuesta aceptada
Steven Lord
el 22 de Abr. de 2021
If you want to check if a number is not in a given set, use ismember.
x = 1:10;
if ismember(5, x)
disp("5 is in x")
else
disp("5 is not in x")
end
if ismember(pi, x)
disp("pi is in x")
else
disp("pi is not in x")
end
0 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Loops and Conditional Statements en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!