BVP4C Unable to solve the collocation equations -- a singular Jacobian encountered
17 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Hello, I am receiving this error attempting to solve a 2nd order ODE with BVP4c.
I am solving for the internal temperature distribution of a nuclear fuel rod using the ode:
with Boundary Conditions:
where R = 0.2m and is the outer diameter
Let me know if you need anything else.
q and k are constants
r is a radius variable
%These are my setup functions.
function dydx = rod_BV(r,y) % Details ODE to be solved
dydx = zeros(2,1);
dydx(1) = y(2)
dydx(2) = -(q/k)-((1/r)*y(1)) % This equation is invalid at r = 0
end
function res = rod_BC(ya,yb) % Details boundary conditions
res = zeros(2,1);
res(1) = ya(2);
res(2) = yb(1) - T_s;
end
% here is my implementation of BVP4C
solinit = bvpinit(linspace(0,R,4),[0,0]); % I have tried setting these 0 values to realmin
options = bvpset('RelTol', 10e-4,'AbsTol',10e-7);
sol = bvp4c(@rod_BV,@rod_BC,solinit,options)
0 comentarios
Respuestas (2)
Divija Aleti
el 24 de Jun. de 2021
Hi Luke,
A singular Jacobian indicates that the initial guess causes the solution to diverge. The BVP4C function finds the solution by solving a system of nonlinear algebraic equations. Nonlinear solvers are only as effective as the initial guess they start with, so changing your starting guess may help. Also, BVP4C is responsible for providing a guess for the solution from one iteration to another.
A detailed explanation and possible solutions for this error are given in the link below:
Also, based on the picture of the equation you are solving, I believe the rod_BV function should be written as follows:
function dydx = rod_BV(r,y) % Details ODE to be solved
dydx = zeros(2,1);
dydx(1) = y(2)
dydx(2) = -(q/r)-((1/r)*y(2)) % This equation is invalid at r = 0
end
This is because T = y(1), T' = y(2), which implies, T'' = -(q/r)-(1/r)*y(2).
Hope this helps!
Regards,
Divija
0 comentarios
MOSLI KARIM
el 31 de Jul. de 2022
Editada: Torsten
el 31 de Jul. de 2022
Hi, here is the solution that I propose to you
%These are my setup functions.
R=0.2;
q=1;
k=1;
eps=1.0000e-06;
r=linspace(0,R,4);
solinit = bvpinit(linspace(0,R,4),[0,0]); % I have tried setting these 0 values to realmin
options = bvpset('RelTol', 10e-4,'AbsTol',10e-7);
sol = bvp4c(@(r,y)rod_BV(r,y,q,k),@rod_BC,solinit,options);
y=deval(sol,r);
plot(r,y(1,:))
function dydx = rod_BV(r,y,q,k) % Details ODE to be solved
dydx = zeros(2,1);
dydx(1) = y(2);
dydx(2) = -(q/k)-((1/(r+eps))*y(1)) ; % This equation is invalid at r = 0
end
function res = rod_BC(ya,yb) % Details boundary conditions
%res = zeros(2,1);
% res(1) = ya(2);
% res(2) = yb(1) - 200;
res=[ya(2);yb(1)-200];
end
% here is my implementation of BVP4C
% solinit = bvpinit(linspace(0,R,4),[0,0]); % I have tried setting these 0 values to realmin
% options = bvpset('RelTol', 10e-4,'AbsTol',10e-7);
% sol = bvp4c(@rod_BV,@rod_BC,solinit,options)
2 comentarios
Torsten
el 31 de Jul. de 2022
I think it must be
dydx(2) = -(q/k)-((1/(r+eps))*y(2)) ; % This equation is invalid at r = 0
instead of
dydx(2) = -(q/k)-((1/(r+eps))*y(1)) ; % This equation is invalid at r = 0
Ver también
Categorías
Más información sobre Boundary Value Problems en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!