how to preform Laplace transform?

for i=late+1:length(x)  
   delayed_signal(i) = x(i)+alpha*x(i-late);  
 end  
 app.y = delayed_signal;
 app.x_n = x;
 x_s = laplace(x);
 y_s = laplace(delayed_signal);
 h_s = x_s/y_s;

I am tring to Laplace tranform the variable 'x': a .wav folder, read through 'audioread

and 'y' the same file with an echo, and then divide them and put them in 'h_s', but I keep getting the following error at the line where I define 'y_s'

 Undefined function 'laplace' for input arguments of type 'double'

can someone please explain what this line means and how to fix it? - TIA

Answer 1

[Matt J]

The laplace() command only works on Symbolic Math Toolbox variables, e.g.,

 syms y(t)
 y=exp(-t).*heaviside(t);
 
 Y=laplace( y )

Y = 

[Adham Elkhouly]

Thank you for your reply - is there a way I can fix this and make it work in my scenario?

[Matt J]

A Laplace transform in this scenario doesn't make a lot of sense to me. At what values of s would you want the Laplace transform evaluated?

[Adham Elkhouly]

I am trying to find the h(s) between the sound and its echo in laplace transform

x(t) * h(t) = y(t) <--using convolution

x(s) . h(s) = y(s)

and then use the inverse transform to find h(t), which is the other variavle in convolution. is this idea implementable in MATLAB?

[Matt J]

Why with Laplace transforms? Why not with FFTs?

[Matt J]

or deconv().

[Adham Elkhouly]

I am a bit of a beginner in using MATLAB, so I don't really know what FFT is but I will look it up