How to display results for looping

helle everyone.. I would like to ask a question regarding to my programming. I have this code as below. I want to display all the result for each iteration. which part do I need to put the syntax so that it can store the result from 1st iteration till 5th and display all the result (x1_new,x2_new,y_new) when the loop is done..

clc clear a=5; alpha=0.2

x1=ceil(rand(a,1)*10); x2=ceil(rand(a,1)*10); y=x1+x2 data=[x1 x2 y]

for n=1:5 for i=1:5 if y(n)<y(i)

        r=(data(n,1)-data(i,1))^2+(data(n,2)-data(i,2))^2
        p=sqrt(r)

        x1_new=ceil(data(i,1)+exp(-p^2)*(data(i,1)-data(i,1))+alpha.*(rand-0.5))
        x2_new=ceil(data(i,2)+exp(-p^2)*(data(i,2)-data(i,2))+alpha.*(rand-0.5))
        y_new=x1_new(i)+x2_new
    else
        x1_new=data(i,1)
        x2_new=data(i,2)
        y_new=data(i,3)
      end
    end
    end
end

tq for your help..

Answer 1

[per isakson]

The results need to be arrays, i.e.

    x1_new(n,i) 
    x2_new(n,i)
    y_new(n,i)

Answer 2

[Suizwati]

I have put that arrays as suggested.. But it doesn't woks and display an error (??? Subscripted assignment dimension mismatch.). How I can solve this problems? Is it correct the syntax that I have been put on my programming as below?

clc clear a=5; alpha=0.2

x1=ceil(rand(a,1)*10); x2=ceil(rand(a,1)*10); y=x1+x2 data=[x1 x2 y]

for n=1:5 for i=1:5 if y(n)<y(i)

        r=(data(n,1)-data(i,1))^2+(data(n,2)-data(i,2))^2
        distance=sqrt(r)

        x1_new(n,i)=ceil(data(i,1)+exp(-distance^2)*(data(i,1)-data(i,1))+alpha.*(rand-0.5))
        x2_new(n,i)=ceil(data(i,2)+exp(-distance^2)*(data(i,2)-data(i,2))+alpha.*(rand-0.5))
        y_new(n,i)=x1_new(i)+x2_new
    else
        x1_new(n,i)=data(i,1)
        x2_new(n,i)=data(i,2)
        y_new(n,i)=data(i,3)
        result(n,i)=[x1_new(n,i) x2_new(n,i)  y_new(n,i)]
      end

    end

end

[Image Analyst]

http://blogs.mathworks.com/videos/2012/07/03/debugging-in-matlab/

Answer 3

[Image Analyst]

In the line

result(n,i)=[x1_new(n,i) x2_new(n,i)  y_new(n,i)]

you're trying to stuff 3 elements into a single result element. You can't do that. You can put only 1 element into that element.