pole placement in M-file
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hello every one ... how can i determine (p) in pole placement code K = place(A,B,p)
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Más respuestas (3)
Shashank Prasanna
el 20 de Jul. de 2013
1 voto
shahad, place is used to perform pole placement using state feedback. The output K is the feedback gain matrix.
PLACE is not an optimal control methodology and does no come up with good p values. It merely attempts to place at the specified location and generates the gain matrix.
You question seems to be related to: How do I generate this stable optimal p?
There are numerous answers to that question but a popular one is linear quadratic controller (LQR):
The first output argument is the gain matrix K and the 3rd output argument 'e' are you poles which are automatically generated when the optimization is performed.
4 comentarios
Azzi Abdelmalek
el 21 de Jul. de 2013
Shashank, even when you do not use optimal control, the chosen poles have to be optimal.
Shashank Prasanna
el 21 de Jul. de 2013
Azzi, I apologize if I interpreted this wrong, but do you mean stable when you say it has to be optimal? Using place you can place the poles anywhere you want for state feedback (as long as A and B are controllable), but shahad, as I interpreted his question, is interested in placing them optimally, and optimal control is a good place to start.
Azzi Abdelmalek
el 16 de Ag. de 2013
Shashank, What I mean by optimal poles is poles that provide a system optimal performances (acceptable stability margin, and optimal performances to be defined by the user).
Azzi Abdelmalek
el 20 de Jul. de 2013
Editada: Azzi Abdelmalek
el 20 de Jul. de 2013
p is the poles vector you have to impose to your system in closed loop.
Example:
A=[-6 -5;1 0];
b=[1;0]
The size of A is 2x2 then the length of the pole vector p should be 2
p=[-5 -10] % the poles should be stables (real(p)<0)
%or
p=[-2+j -2-j]
place(A,b,p)
4 comentarios
Azzi Abdelmalek
el 20 de Jul. de 2013
p should contains 6 stables poles
% For example
p=[-1 -2 -3 -4 -5 -6]
cmcm
el 20 de Jul. de 2013
Azzi Abdelmalek
el 20 de Jul. de 2013
Like I said the pole to impose should be real or complex numbers with real part obligatory negative. This is enough to get a stable control, for optimal performances, you have to read the effects of poles on the system.
A=[-6 -5;1 0];
b=[1;0]
p=[-5 -10] % the poles should be stables (real(p)<0)
%or
p=[-2+j -2-j]
place(A,b,p)
1 comentario
Hi @Nagesh
Your response didn't fully address the original question. In order to determine the control gain using the place() command, the user must input the poles that result in the Hurwitz characteristic polynomial. These poles specifically correspond to the closed-loop system and generate the desired response specified by the user. Your answer deserves votes if you could provide a practical example to illustrate this.
Let's consider a simple Double Integrator system. If we need to meet performance specifications such as a percent overshoot of ≤ 9% and a settling time of ≤ 1 second, how would you determine the target poles?
A = [0, 1; 0, 0]; % state matrix
B = [0; 1]; % input matrix
C = [1, 0]; % output matrix
D = 0*C*B; % direct matrix
sys = ss(A, B, C, D)
Gp = tf(sys)
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