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I need to plot the sum of 2 sine curves. I can successfully plot (x,y1) and plot(x,y2), they are smooth curves, however when i try to plot(x,y) where y = y1+y2 the curve comes out like this? how do i fix this i dont know what i am doing wrong? Thanks

3 comentarios

Stephen23
Stephen23 el 11 de Mayo de 2021
Editada: Stephen23 el 11 de Mayo de 2021
"...however when i try to plot... the curve comes out like this"
You are plotting lots of zeros (to within floating point precision), because that is exactly what you calculated.
"how do i fix this i dont know what i am doing wrong?"
You need to consider the B factor. Note that for a B which is an integer multiple of 2*pi (and you defined B as 4*pi, which is clearly a multiple of 2*pi), the following identity holds true:
sin(B*X) = -sin(B*(1-X))
For example:
B = 2*pi;
X = rand(1,9);
sin(B*X)
ans = 1×9
-0.6044 -0.8824 -0.4910 -0.9397 -0.7891 0.9338 0.8413 0.9918 -0.9736
sin(B*(1-X))
ans = 1×9
0.6044 0.8824 0.4910 0.9397 0.7891 -0.9338 -0.8413 -0.9918 0.9736
That is why you are plotting zeros (or at least values very very very close to zero).
Stephen23
Stephen23 el 16 de Mayo de 2021
Editada: Stephen23 el 16 de Mayo de 2021
Original question by Tyler Daines retrieved from Google Cache (unfortunately their deleted comments are not included):
Trying to plot a sine+sine function but not getting a smooth curve
I need to plot the sum of 2 sine curves. I can successfully plot (x,y1) and plot(x,y2), they are smooth curves, however when i try to plot(x,y) where y = y1+y2 the curve comes out like this? how do i fix this i dont know what i am doing wrong? Thanks
Rena Berman
Rena Berman el 29 de Jun. de 2021

(Answers Dev) Restored edit

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Respuestas (2)

DGM
DGM el 11 de Mayo de 2021

0 votos

What you're looking at isn't meaningful. It's all just rounding error. You're essentially doing this:
y = sin(x) - sin(x);
I'm guessing there's some phase component that's not defined right yet, but I can't really guess at what you need it to be.
f = 2;
A = 1;
v = 1;
L = 1;
l = v/f;
B = (2*pi)/l;
w = 2*pi*f;
t = 0;
x = 0:0.0001:L;
z1 = A*sin(B*x - w*t);
z2 = A*sin(B*(L-x) - w*t);
y = z1+z2;
plot(x,z2); hold on
plot(x,z1);
For the future, please just paste your code using the code formatting tools. I had to retype all that and deal with the sub-pixel ambiguity differentiating the character '1' and 'l'.

2 comentarios

Tyler Daines
Tyler Daines el 11 de Mayo de 2021
Sorry mate i havent used this forum before will do in the future.
DGM
DGM el 11 de Mayo de 2021
No worries. It was short enough.

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RAHUL MAURYA
RAHUL MAURYA el 12 de Mayo de 2021

0 votos

clear all;
clc;
f = 2;
A = 1;
v = 1;
L = 1*(180/(pi));
l = v/f;
B = ((2*pi)/l)*(180/pi);
w = 2*pi*f;
t = 0;
x=0:0.0001:L;
z1 = (A*sind(B*x - w*t));
z2 = A*sind(B*(L-x) - w*t);
y=(z1+z2);
subplot(3,1,1);
plot(x,z1)
title('X,Z1')
axis([0 10 -1 1])
subplot(3,1,2);
plot(x,z2)
title('X,Z2')
axis([0 10 -1 1])
subplot(3,1,3);
plot(x,y)
title('X,Z1+Z2')
axis([0 10 -2 2])
Convert B and L in radian to degree.

Preguntada:

el 11 de Mayo de 2021

Editada:

el 29 de Jun. de 2021

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